[英]output a number in a line with specific string using sed linux
我有一个像下面这样的输入。
Curveplot
Time
Maxima of Curve
Part no.
13 #pts=2
* Minval= 0.000000e+000 at time= 0.000000
* Maxval= 2.237295e+000 at time= 0.001000
0.000000e+000 0.000000e+000
9.999999e-004 2.237295e+000
endcurve
我想从这个文件中获取最大值,这是Maxval之后的值
* Maxval= 2.237295e+000
有人可以建议如何用linux sed做到这一点? 我的输出只有2.237295e + 000。
使用以下单行将仅显示2.237295e+000
sed -nr 's/.*Maxval= *([^ ]*).*/\\1/p'
正则表达式:
Match:
.* # match any characters
Maxval= # upto 'Maxval='
* # match multiple spaces (that is a space followed by *)
([^ ]) # match anything not a space, use brackets to capture (save this)
.* # match the rest of line
Replace with:
\1 # the value that a was captured in the first set of brackets.
所以我们实际上代替包含单词整行Maxval=
由值Maxval
。
注意:根据平台和/或sed
的实现,您可能需要使用-E
而不是-r
。
单程:
sed -n 's/.*Maxval=\s*\([^ ]*\).*/\1/p' file.txt
结果:
2.237295e+000
提案:
cat test.txt | grep Maxval | sed -e 's/^.*Maxval= *//' -e 's/ at.*$//' 2.237295e+000
awk '/Maxval=/{print $3}' your_file
测试如下:
> cat temp
Curveplot
Time
Maxima of Curve
Part no.
13 #pts=2
* Minval= 0.000000e+000 at time= 0.000000
* Maxval= 2.237295e+000 at time= 0.001000
0.000000e+000 0.000000e+000
9.999999e-004 2.237295e+000
endcurve
> awk '/Maxval=/{print $3}' temp
2.237295e+000
你也可以用grep来做:
<infile grep -o 'Maxval= *[^ ]\+' | grep -o '[^ ]\+$'
输出:
2.237295e+000
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