您如何解析名称中带有冒号的 JSON？ 安卓/Java

Question

例如： { "primary:title":"Little Red Riding Hood"}

由于主要和标题之间的冒号，我的 Java (Android) 解析器总是卡住。 我可以轻松解析任何其他内容，我只需要这方面的帮助。

public class MainActivity extends Activity {
    /** Called when the activity is first created. */

    TextView txtViewParsedValue;

    private JSONObject jsonObject;
    private JSONArray jsonArray;

    String [] titles, links, mediaDescriptions, mediaCredits, descriptions, dcCreators, pubDates, categories;
    String [] permalinks, texts;            // guid
    String [] rels, hrefs;
    String [] urls, media, heights, widths; // media:content

    String strParsedValue = "";

    private String strJSONValue;

    @Override
    public void onCreate(Bundle savedInstanceState) {
        super.onCreate(savedInstanceState);
        setContentView(R.layout.activity_main);

        strJSONValue = readRawTextFile(this, R.raw.jsonextract);

        txtViewParsedValue = (TextView) findViewById(R.id.text_view_1);

        try {
            parseJSON();

        } catch (JSONException e) {
            // TODO Auto-generated catch block
            e.printStackTrace();
        }
    }

    public void parseJSON() throws JSONException
    {
        txtViewParsedValue.setText("Parse 1");

        jsonObject = new JSONObject(strJSONValue);
        jsonArray = jsonObject.getJSONArray("item");

        titles = new String[jsonArray.length()];
        links = new String[jsonArray.length()];
        permalinks = new String[jsonArray.length()];
        texts = new String[jsonArray.length()];
        mediaDescriptions = new String[jsonArray.length()];
        mediaCredits = new String[jsonArray.length()];
        descriptions = new String[jsonArray.length()];
        dcCreators = new String[jsonArray.length()];
        pubDates = new String[jsonArray.length()];
        categories = new String[jsonArray.length()];

        txtViewParsedValue.setText("Parse 2");

        for (int i=0; i<jsonArray.length(); i++)
        {
            JSONObject object = jsonArray.getJSONObject(i);

            titles[i] = object.getString("title");
            links[i] = object.getString("link");

            JSONObject guidObj = object.getJSONObject("guid");
            permalinks[i] = guidObj.getString("isPermaLink");
            texts[i] = guidObj.getString("text");
            //mediaDescriptions[i] = object.getString("media:description");
            //mediaCredits[i] = object.getString("media:credit");

                // *** THE PARSER FAILS IF THE COMMENTED LINES ARE IMPLEMENTED BECAUSE
                // OF THE : IN BETWEEN THE NAMES ***

            descriptions[i] = object.getString("description");
            //dcCreators[i] = object.getString("dc:creator");
            pubDates[i] = object.getString("pubDate");
            categories[i] = object.getString("category");   
        }



        for (int i=0; i<jsonArray.length(); i++)
        {
            strParsedValue += "\nTitle: " + titles[i];
            strParsedValue += "\nLink: " + links[i];
            strParsedValue += "\nPermalink: " + permalinks[i];
            strParsedValue += "\nText: " + texts[i];
            strParsedValue += "\nMedia Description: " + mediaDescriptions[i];
            strParsedValue += "\nMedia Credit: " + mediaCredits[i];
            strParsedValue += "\nDescription: " + descriptions[i];
            strParsedValue += "\nDC Creator: " + dcCreators[i];
            strParsedValue += "\nPublication Date: " + pubDates[i];
            strParsedValue += "\nCategory: " + categories[i];
            strParsedValue += "\n";
        }


        txtViewParsedValue.setText(strParsedValue);
    }

    public static String readRawTextFile(Context ctx, int resId)
    {
         InputStream inputStream = ctx.getResources().openRawResource(resId);

            InputStreamReader inputreader = new InputStreamReader(inputStream);
            BufferedReader buffreader = new BufferedReader(inputreader);
             String line;
             StringBuilder text = new StringBuilder();

             try {
               while (( line = buffreader.readLine()) != null) {
                   text.append(line);
                   //text.append('\n');
                 }
           } catch (IOException e) {
               return null;
           }
             return text.toString();
    }

Answer 1

一方面，为了回答您的问题，JSONObject 和 org.json.* 类没有问题，如果它们格式正确，则解析其中带有冒号的键。 以下单元测试通过，这意味着它能够解析您的示例场景：

public void testParsingKeysWithColons() throws JSONException {
    String raw = "{ \"primary:title\":\"Little Red Riding Hood\"}";
    JSONObject obj = new JSONObject(raw);
    String primaryTitle = obj.getString("primary:title");
    assertEquals("Little Red Riding Hood", primaryTitle);
}

另一个建议是，将字符串数组用于数据是笨拙的，使用数据结构来表示对象会更好地组织起来。 而不是标题、链接、描述的字符串数组； 使用具有这些属性的对象并列出这些对象。 例如：

public class MyDataStructure {

    public String title;
    public String primaryTitle;
    public String link;
    public String mediaDescription;

    public static class Keys {
        public static String title = "title";
        public static String primaryTitle = "primary:title";
        public static String link = "link";
        public static String mediaDescription = "media:description";
    }

}

然后你可以创建一个“翻译器”类，为你做所有的解析并返回你的对象列表。 这更容易使用和跟踪。 您永远不必考虑数据未对齐或其中一个阵列中的数据比您预期的多或少。 如果您的输入数据丢失任何内容或任何 json 格式错误，您也可以更轻松地测试问题出在哪里。

public class MyDataStructureTranslator {

    public static List<MyDataStructure> parseJson(String rawJsonData) throws JSONException {

        List<MyDataStructure> list = new ArrayList<MyDataStructure>();
        JSONObject obj = new JSONObject(rawJsonData);
        JSONArray arr = obj.getJSONArray("item");

        for(int i = 0; i < arr.length(); i++) {
            JSONObject current = arr.getJSONObject(i);
            MyDataStructure item = new MyDataStructure();
            item.title = current.getString(MyDataStructure.Keys.title);
            item.primaryTitle = current.getString(MyDataStructure.Keys.primaryTitle);
            item.link = current.getString(MyDataStructure.Keys.link);
            item.mediaDescription = current.getString(MyDataStructure.Keys.mediaDescription);
            list.add(item);
        }

        return list;
    }

}

Answer 2

由于 Java 标识符不能有冒号，因此只需指定一个映射到确切 json 名称的 json 属性名称，例如：

@JsonProperty("primary:title")
public String primaryTitle;