在Centos 6.2（64位）上编译Apache 2.4.3

Question

我尝试在Centos 6.2（64位）上使用apr-1.4.6和apr-util-1.5.1编译Apache 2.4.3。

./configure --build = x86_64-unknown-linux-gnu --host = x86_64-unknown-linux-gnu --target = x86_64-redhat-linux-gnu --program-prefix = --prefix = / usr - exec-prefix = / usr --bindir = / usr / bin --sbindir = / usr / sbin --sysconfdir = / etc --datadir = / usr / share --includedir = / usr / include --libdir = / usr / lib64 --libexecdir = / usr / libexec --localstatedir = / var --sharedstatedir = / var / lib --mandir = / usr / share / man --infodir = / usr / share / info --cache-file = ../config.cache --with-libdir = lib64 --with-config-file-path = / etc --with-config-file-scan-dir = / etc / php.d --disable-debug - with-pic --disable-rpath --without-pear --with-bz2 --with-exec-dir = / usr / bin --with-freetype-dir = / usr --with-png-dir = / usr --with-xpm-dir = / usr --enable-gd-native-ttf --with-t1lib = / usr --without-gdbm --with-gettext --with-gmp --with-iconv --with -jpeg-dir = / usr --with-openssl --with-zlib --with-layout = GNU --enable-exif --enable-ftp --enable-magic-quotes --enable-sockets --with- kerberos --enable-ucd-snmp-hack --enable-shmop --enable-calendar --with-libxml-dir = / usr --enable-xml --with-system-tzdata --with-mhash --with-apxs2 = / usr / sbin / apxs --libdir = / usr / lib64 / php --enable-pdo = shared - with-mysql = shared，/ usr --with-mysqli = shared，/ usr / lib64 / mysql / mysql_config --with-pdo-mysql = shared，/ usr / lib64 / mysql / mysql_config --without-pdo-sqlite - -without-gd --disable-dom --disable-dba --without-unixODBC --disable-xmlreader --disable-xmlwriter --without-sqlite3 --disable-phar --disable-fileinfo --disable-json - -without-pspell --disable-wddx --without-curl --disable-posix --disable-sysvmsg --disable-sysvshm --disable-sysvsem ./configure --with-included-apr --with-included- APR-UTIL

当我发出让这件事发生时：

/root/httpd-2.4.3/srclib/apr/libtool:line 5989：cd：yes / lib：没有这样的文件或目录libtool：link：无法确定yes/lib' make[3]: *** [libaprutil-1.la] Error 1 make[3]: Leaving directory绝对目录名yes/lib' make[3]: *** [libaprutil-1.la] Error 1 make[3]: Leaving directory /root/httpd-2.4.3/srclib/apr-util'make [2]： * [all-recursive]错误1 make [2]：离开目录/root/httpd-2.4.3/srclib/apr-util' make[1]: *** [all-recursive] Error 1 make[1]: Leaving directory /root/httpd-2.4.3/srclib' make：* [all-recursive]错误1

我错过了什么？

Answer 1

请执行以下操作：

# Build and install apr 1.2
 cd srclib/apr
 ./configure --prefix=/usr/local/apr-httpd/
 make
 make install

 # Build and install apr-util 1.2
 cd ../apr-util
 ./configure --prefix=/usr/local/apr-util-httpd/ --with-apr=/usr/local/apr-httpd/
 make
 make install

 # Configure httpd
 cd ../../
 ./configure --with-apr=/usr/local/apr-httpd/ --with-apr-util=/usr/local/apr-util-httpd/ 

Answer 2

以上让我能够安装apache 2.4.3。 不幸的是，对我来说，也许你也是，我在做apachectl -k启动时看到了这个：

httpd：/home/netman1/sp/usr/local/apache/conf/httpd.conf第141行的语法错误：无法将modules / mod_dir.so加载到服务器：home / netman1 / sp / usr / local / apache / modules /mod_dir.so：未定义的符号：apr_array_clear

我做到了这一点，发现一个陈旧的链接指向旧版本的libapr-1.so。

ldd httpd | grep apr libaprutil-1.so.0 => /home/netman1/usr/local/apache/apr/lib/libaprutil-1.so.0(0x00002aba9dccb000)libapr-1.so.0 => / usr / lib64 / libapr-1.so.0（0x00002aba9defd000）

为了解决这个问题，我保存了旧的链接，然后创建了一个指向正确版本的新链接：

fixed: libapr-1.so.0 -> /opt/app/p3smk1c1/usr/local/apache/apr/lib/libapr-1.so.0.4.6
broken: libapr-1.so.0 -> libapr-1.so.0.2.7

现在，我可以启动apache，至少它不会抱怨'未定义的符号：apr_array_clear'...希望这会对你有所帮助。