在MySQL中通过代码获取带有min（price）组的行的值

Question

我的表结构是这样的：

country                 | price  | code
---------------------------------------
EGYPT PROPER  WHOLESALE | 0.037  | 20
EGYPT FIXED             | 0.0710 | 20
EGYPT-OTHER             | .0497  | 20

我必须使用GROUP BY代码，并且我希望输出为：

country                 | price  | code
---------------------------------------
EGYPT PROPER  WHOLESALE | 0.037  | 20

具有最低价格。

我的查询是：

select MIN(inp.price) as Price, inp.code, inp.country
from tbl_input_values as inp 
GROUP BY code

但我得到的输出为：

country         | price | code
------------------------------
EGYPT-OTHER     | .037  | 20

Answer 1

这里，

SELECT  *
FROM    tbl_input_values
WHERE   price = (SELECT MIN(PRICE) FROM tbl_input_values)

• SQLFiddle演示

Answer 2

对于每个代码，这将显示具有最低价格的行：

SELECT yourtable.*
FROM yourtable
WHERE (code, price) IN (select code, min(price)
                        from yourtable
                        group by code)

Answer 3

带有多个代码：

SELECT tb1.* 
FROM tbl_input_values tb1
INNER JOIN (select code, min(price) minPrice
            FROM tbl_input_values
            GROUP BY code) as a
   ON a.code = tb1.code and a.minPrice =tb1.price

Answer 4

我认为最简单的方法是：

select t.*
from t
order by price
limit 1

您根本不需要聚合。