在MySQL中通過代碼獲取帶有min（price）組的行的值

Question

我的表結構是這樣的：

country                 | price  | code
---------------------------------------
EGYPT PROPER  WHOLESALE | 0.037  | 20
EGYPT FIXED             | 0.0710 | 20
EGYPT-OTHER             | .0497  | 20

我必須使用GROUP BY代碼，並且我希望輸出為：

country                 | price  | code
---------------------------------------
EGYPT PROPER  WHOLESALE | 0.037  | 20

具有最低價格。

我的查詢是：

select MIN(inp.price) as Price, inp.code, inp.country
from tbl_input_values as inp 
GROUP BY code

但我得到的輸出為：

country         | price | code
------------------------------
EGYPT-OTHER     | .037  | 20

Answer 1

這里，

SELECT  *
FROM    tbl_input_values
WHERE   price = (SELECT MIN(PRICE) FROM tbl_input_values)

• SQLFiddle演示

Answer 2

對於每個代碼，這將顯示具有最低價格的行：

SELECT yourtable.*
FROM yourtable
WHERE (code, price) IN (select code, min(price)
                        from yourtable
                        group by code)

Answer 3

帶有多個代碼：

SELECT tb1.* 
FROM tbl_input_values tb1
INNER JOIN (select code, min(price) minPrice
            FROM tbl_input_values
            GROUP BY code) as a
   ON a.code = tb1.code and a.minPrice =tb1.price

Answer 4

我認為最簡單的方法是：

select t.*
from t
order by price
limit 1

您根本不需要聚合。