[英]Indexing an array pointed to by a pointer within a Structure
看看我以前的问题 。 我用这组代码得到了解决方案
const MEMBERS *some_members = (MEMBERS *) GET_MEM();
unsigned value1 = some_members->mem1;
unsigned value2 = *some_members->mem2;
没有像我预期的那样工作。 但是在样本是的情况下
unsigned sample [4] = {2,5,6,1};
如果我需要从结构中对数组的第3个字符(即sample [3] = 1。)进行索引,我该如何在数组中进行索引。 我也将value2作为指针吗?
谢谢大家......
在这种情况下,是的,使value2
成为指针。 以机智:
const MEMBERS *some_members = (MEMBERS *) GET_MEM();
unsigned value1 = some_members->mem1;
unsigned *value2 = some_members->mem2;
// These are true statements
value2[0] == 2;
value2[1] == 5;
value2[2] == 6;
value2[3] == 1;
指针和数组可以被访问。
例如:
int array[4] = { 1, 2, 3, 4 };
printf("Third entry in array = %d\n", array[2]);
int *pointer = array;
printf("Third entry in array using pointer = %d\n", pointer[2]);
如果指针在结构中与否无关紧要,只需使用普通字段访问(例如structure.pointer[2]
或structpointer->pointer[2]
)。
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