[英]SQL CLR C# User Defined Function - Get house or flat number from address
我有以下SQL CLR C#UDF:
using System;
using System.Data;
using System.Data.SqlClient;
using System.Data.SqlTypes;
using Microsoft.SqlServer.Server;
using System.Collections;
using System.Text;
public partial class UserDefinedFunctions
{
[Microsoft.SqlServer.Server.SqlFunction]
public static SqlString clrFn_GetDigits(string theWord)
{
if (theWord == null) { theWord = ""; }
string newWord = "";
char[] KeepArray = { '0', '1', '2', '3', '4', '5', '6', '7', '8', '9', '\\', '/', '-', ' '};
foreach (char thischar in theWord)
{
foreach (char keepchar in KeepArray)
{
if (keepchar == thischar)
{
newWord += thischar;
}
}
}
return (SqlString)(newWord.Trim());
}
}
到目前為止,除以下類似地址外,此方法都有效:
141A, Some Street Avenue
4b, St Georges Street
16E Test Avenue
我希望我的函數返回141A,4b和16E
有任何想法嗎?
我沒有測試下面的代碼,但是根據這些內容,需要進行一些錯誤檢查以確保轉換不會失敗,但是此解決方案可以為您提供所需的東西
char[] KeepArray = { '0', '1', '2', '3', '4', '5', '6', '7', '8', '9', '\\', '/', '-', ' ' };
foreach (char thischar in theWord) {
if (KeepArray.Contains(thischar)) {
newWord += thischar;
}
else if (Char.IsLetter(thischar) && newWord.Length > 0){
try {
if (Char.IsDigit((Convert.ToChar(newWord.Substring(newWord.Length - 1, 1))))) {
newWord += thischar;
}
}
catch {
}
}
}
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