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在prolog中的謂詞中定義謂詞

[英]Define a predicate inside a predicate in prolog

我正在嘗試將謂詞內聯定義為將其傳遞給Prolog中的另一個謂詞。

% Test if a "product" of graphs G1 and G2 has a "mini-loop" starting from Q
test_property_combined(G1,G2,Q):-
    (g12(Q1,Q2) :- combine(G1,G2,Q1,Q2)),
    some_property(g12,Q).

(上面的語法顯然是錯誤的。)

后來, g12將通過調用call

% Test if a graph G has a "mini-loop" starting from Q
some_property(G,Q):-
    Goal1 =.. [G,Q,C],
    Goal2 =.. [G,C,Q],
    call(Goal1),
    call(Goal2).

問題仍然存在,因為我想在某種先前定義的謂詞聚合上測試some_property

% Create a "product" of graphs G1 and G2
combine(G1,G2,(Q1,Q2),(Q3,Q4)):-
    Goal1 =.. [G1,Q1,Q3],
    Goal2 =.. [G2,Q2,Q4],
    call(Goal1),
    call(Goal2).

提到的謂詞和測試查詢的示例:

% g1 and g2 are graphs
g1(a,b).
g1(b,a).

g2(c,d).
g2(d,c).


?- test_property_combined(g1,g2,(a,c)).

怎么去做呢?

我不確定這一點,但這有效:

test_property_combined(G1,G2,Q):-
    assert((g12(Q1,Q2) :- combine(G1,G2,Q1,Q2))),
    some_property(g12,Q).

好吧,可能是那樣的

:- use_module(library(lambda)).

test_property_combined(G1,G2,Q):-
    % (g12(Q1,Q2) :- combine(G1,G2,Q1,Q2)),
    Pred = \Z^T^combine(G1,G2,Z,T),
    some_property(Pred,Q).


combine(G1,G2,(Q1,Q2),(Q3,Q4)):-
    Goal1 =.. [G1,Q1,Q3],
    Goal2 =.. [G2,Q2,Q4],
    call(Goal1),
    call(Goal2).


some_property(G,Q):-
    call(G, Q, C),
    call(G, C, Q).

最后編輯(希望如此),完整代碼:

test_property_combined(G1,G2,Q):-
    some_property(combine(G1,G2),Q).

combine(G1,G2,(Q1,Q2),(Q3,Q4)):-
    call(G1,Q1,Q3),
    call(G2,Q2,Q4).

some_property(G,Q):-
    call(G, Q, C),
    call(G, C, Q).

g1(a,b).
g1(b,a).

g2(c,d).
g2(d,c).

@false =>有用的評論,像往常一樣!

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