查找具有兩個相似列和一個不同列的重復項

Question

我處於一種情況下，我需要在兩個特定的列中選擇具有相同內容的行，而在第三列中選擇具有不同內容的行。 到目前為止，我在兩個類似的列中都得到了這個：

SELECT id, Title,
COUNT(*) AS NumOccurrences
FROM Table
GROUP BY id, Title
HAVING ( COUNT(*) > 1 )

現在，我需要在此查詢中指定第三個不同的列。 我們稱它為拉爾夫（Ralph）。 這顯然行不通：

SELECT id, Title, DISTINCT Ralph,
COUNT(*) AS NumOccurrences
FROM Table
GROUP BY id, Title
HAVING ( COUNT(*) > 1 )

那會怎樣？

Answer 1

select * from (
    SELECT id, Title, COUNT(*) AS NumOccurrences
    FROM Table t
    GROUP BY id, Title
    HAVING ( COUNT(*) > 1 )
) t
cross apply (
    select distinct Ralph
    from Table
    where id = t.id and Title = t.Title
) t2

Answer 2

您可以將COUNT（*）與OVER（）子句一起使用

 ;WITH cte AS
 (       
  SELECT id, Title, Ralph, COUNT(*) OVER (PARTITION BY id, Title) AS cnt
  FROM dbo.test11
  GROUP BY id, Title, Ralph
  ) 
  SELECT *
  FROM cte
  WHERE cnt > 1

關於SQLFiddle的演示