[英]Add root element attribute
我正在序列化如下所示的類
XmlSerializerNamespaces namespaces = new XmlSerializerNamespaces();
namespaces.Add(string.Empty, string.Empty);
StringWriter sw = new StringWriter();
XmlSerializer serializer1 = new XmlSerializer(typeof(List<student>), new XmlRootAttribute("Response"));
XmlTextWriter xmlWriter = new XmlTextWriter(sw);
serializer1.Serialize(xmlWriter, ls, namespaces);
sw.ToString()
下面的結果字符串
<?xml version="1.0" encoding="utf-16"?>
<Response><student><name>xxx</name></student></Response>
但是,如何將屬性添加到根元素(響應)? 像下面一個
<?xml version="1.0" encoding="utf-16"?>
<Response status="1"><student><name>xxx</name></student></Response>
您只需要用XmlAttribute標記該類的屬性,即
class MyClass{
[XmlAttribute("status")]
public string ErrorStatus { get; set; }
}
編輯:
剛意識到您正在直接序列化列表。 將您的列表放在父類Response中,然后將上述屬性添加到該Response類中,然后序列化Response對象。
希望這可以幫助。
您可以創建另一個包含該列表的對象,然后創建一個屬性以將該屬性添加到根節點。
訣竅是在此新類中以顯式類型分配給學生類型作為列表的開頭,以避免將您的列表嵌套在另一個父節點中。
[XmlType(TypeName = "Response")]
public class ResponseObject
{
[XmlAttribute("status")]
public string file { get; set; }
[XmlElement("Student", Type = typeof(Student))]
public List<Student> studentList { get; set; }
}
您的代碼將如下所示
XmlSerializerNamespaces namespaces = new XmlSerializerNamespaces();
namespaces.Add(string.Empty, string.Empty);
StringWriter sw = new StringWriter();
XmlSerializer serializer1 = new XmlSerializer(typeof(ResponseObject));
XmlTextWriter xmlWriter = new XmlTextWriter(sw);
//Creating new object and assign the existing list and status
ResponseObject resp = new ResponseObject();
resp.studentList = ls;
resp.status = 1;
//Serialize with the new object
serializer1.Serialize(xmlWriter, resp, namespaces);
sw.ToString()
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