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使用DataContractSerializer反序列化XML

[英]Deserializing XML with DataContractSerializer

我有一個返回以下數據的Web服務:

<?xml version=""1.0"" encoding=""UTF-8""?>
<RESPONSE>
    <KEY>12345</KEY>
    <PROPERTY>
        <PROPERTY_ADDRESS>
            <STREET_NUM>25</STREET_NUM>
            <STREET_ADDRESS>ELM ST</STREET_ADDRESS>
            <STREET_PREFIX/>
            <STREET_NAME>ELM</STREET_NAME>
            <STREET_TYPE>ST</STREET_TYPE>
            <STREET_SUFFIX/>
        </PROPERTY_ADDRESS>
    </PROPERTY>
</RESPONSE>

我有一個匹配的類結構:

[DataContract(Name="RESPONSE", Namespace="")]
public class Response
{
    [DataMember(Name="KEY")]
    public string Key { get; set; }

    [DataMember(Name = "PROPERTY")]
    public Property Property { get; set; }
}

[DataContract(Name="PROPERTY", Namespace="")]
public class Property
{
    [DataMember(Name="PROPERTY_ADDRESS")]
    public PropertyAddress Address { get; set; }
}


[DataContract(Name="PROPERTY_ADDRESS", Namespace="")]
public class PropertyAddress
{
    [DataMember(Name="STREET_NUM")]
    public string StreetNumber { get; set; }

    [DataMember(Name = "STREET_ADDRESS")]
    public string StreetAddress { get; set; }

    [DataMember(Name = "STREET_PREFIX")]
    public string StreetPrefix { get; set; }

    [DataMember(Name = "STREET_NAME")]
    public string StreetName { get; set; }

    [DataMember(Name = "STREET_TYPE")]
    public string StreetType { get; set; }

    [DataMember(Name = "STREET_SUFFIX")]
    public string StreetSuffix { get; set; }
}

我的反序列化代碼如下所示:

[Test]
public void TestMapping()
{
    var serializer = new DataContractSerializer(typeof(Response));

    Response response = null;

    using (var ms = new MemoryStream(Encoding.UTF8.GetBytes(XmlData)))
    {
        response = (Response)serializer.ReadObject(ms);
    }

    //This works
    Assert.AreEqual("12345", response.Key);

    //This works
    Assert.AreEqual("25", response.Property.Address.StreetNumber);

    //This FAILS. StreetAddress is null
    Assert.AreEqual("ELM ST", response.Property.Address.StreetAddress);
}

對於我的生活,我無法弄清楚StreetAddress失敗的原因。 它必須是我想念的簡單事物。

DataContractSerializer期望事物按字母順序排列 您需要將Order添加到數據成員才能使其正常工作。

[DataContract(Name = "PROPERTY_ADDRESS", Namespace = "")]
public class PropertyAddress
{
    [DataMember(Name = "STREET_NUM", Order=0)]
    public string StreetNumber { get; set; }

    [DataMember(Name = "STREET_ADDRESS", Order=1)]
    public string StreetAddress { get; set; }

    [DataMember(Name = "STREET_PREFIX", Order=2)]
    public string StreetPrefix { get; set; }

    [DataMember(Name = "STREET_NAME", Order=3)]
    public string StreetName { get; set; }

    [DataMember(Name = "STREET_TYPE", Order=4)]
    public string StreetType { get; set; }

    [DataMember(Name = "STREET_SUFFIX",Order=5)]
    public string StreetSuffix { get; set; }
}

您必須使用元素的順序來擴充數據協定,因為DataContractSerializer期望默認情況下按字母順序對元素進行排序。 您的XML不是這種情況。

這是代碼:

[DataContract(Name = "PROPERTY_ADDRESS", Namespace = "")]
public class PropertyAddress
{
    [DataMember(Name = "STREET_NUM", Order=1)]
    public string StreetNumber { get; set; }

    [DataMember(Name = "STREET_ADDRESS", Order=2)]
    public string StreetAddress { get; set; }

    [DataMember(Name = "STREET_PREFIX", Order=3)]
    public string StreetPrefix { get; set; }

    [DataMember(Name = "STREET_NAME", Order=4)]
    public string StreetName { get; set; }

    [DataMember(Name = "STREET_TYPE", Order=5)]
    public string StreetType { get; set; }

    [DataMember(Name = "STREET_SUFFIX", Order=6)]
    public string StreetSuffix { get; set; }
}

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