如何創建動態Lambda表達式

Question

我有一個問題，如何添加另一個過濾器，我必須驗證是否已選中？

private Expression < Func < Entity.Modelos.Flux, bool >> Filter() {
    var dateStart = dtpDateStart.Value.Date;
    var dateEnd = dtpDateEnd.Value.Date;

    Expression < Func < Entity.Modelos.Flux, bool >> expr = null;

    expr = f = > f.DatFlux >= dateStart.Date && f.DatFlux <= dateEnd.Date;

    if (txtDescription.Text != String.Empty) {
        //add filter
    }

    return expr;
}

更新：我將使用此函數中的表達式：

public virtual IQueryable < T > Filter(Expression < Func < T, bool >> expressao) {
    return DbSet.Where(expressao).AsQueryable < T > ();
}

我試圖做的是這個，但有一個表達

public List < Users > GetUsers(int ? id, string name) {
    using(DBContext ctx = new DBContext()) {
        IQueryable query = ctx.Usuarios;
        if (id.HasValue)
            query = query.Where(x = > x.ID == id);

        if (!string.IsNullOrEmpty(name))
            query = query.Where(x = > x.Name.StartsWith(name));

        return query.ToList();

    }
}

Answer 1

如果這只是您的需求的演示，那么您可以使用System.Linq.Expressions命名空間創建和修改Expression Trees 。

但是，就您的問題而言，使用EF可能更容易：

bool filterDescription = !String.IsNullOrEmpty( txtDescription.Text );

expr = f =>
  (
    ( f.DatFlux >= dateStart.Date && f.DatFlux <= dateEnd.Date )
    &&
    ( !filterDescription || ... add filter ... )
  )
;

或正常的C＃：

if ( String.IsNullOrEmpty( txtDescription.Text ) )
{
  expr = f => f.DatFlux >= dateStart.Date && f.DatFlux <= dateEnd.Date;
}
else
{
  expr = f => f.DatFlux >= dateStart.Date && f.DatFlux <= dateEnd.Date
    &&
    ... add filter ...
  ;
}

Answer 2

好的，這里有一個關於如何嵌入lambda語句的示例。 這不是你的榜樣，但在這里你走了：

Func<int, int, EventHandler> makeHandler =
    (dx, dy) => (sender, e) => {
        var btn = (Button) sender;
        btn.Top += dy;
        btn.Left += dx;
    };

btnUp.Click += makeHandler(0, -1);
btnDown.Click += makeHandler(0, 1);
btnLeft.Click += makeHandler(-1, 0);
btnRight.Click += makeHandler(1, 0);

Answer 3

這很簡單。訪問此鏈接

棘手的是調用OrderByAlias - 使用MakeGenericMethod可能就是這樣，如上面的鏈接所示。

Answer 4

試試這種方式：

private Expression<Func<Entity.Modelos.Flux, bool>> Filter()
{
    var dateStart = dtpDateStart.Value.Date;
    var dateEnd = dtpDateEnd.Value.Date;

    Func<Entity.Modelos.Flux, bool> expr = null;

    expr = f => f.DatFlux >= dateStart.Date && f.DatFlux <= dateEnd.Date;

    if(txtDescription.Text != String.Empty)
    {
       expr = f => expr(f) && f.Title.Equals(txtDescription.Text); // ← Your additional filter
    }

    return f => expr(f);
}

Answer 5

繼承自ExpressionVisitor

public class MyVisitor: ExpressionVisitor
{
    private LambdaExpression visitor;
    public Expression Modify(Expression expression, LambdaExpression visitor)
    {
        this.visitor = visitor;
        return Visit(expression);
    }

    protected override Expression VisitBinary(BinaryExpression b)
    {
        var binary = visitor.Body as BinaryExpression;

        return Expression.MakeBinary(ExpressionType.AndAlso, b, binary, b.IsLiftedToNull, b.Method);
    }
}

您的Filter()方法可能如下所示

    private Expression<Func<Entity.Modelos.Flux, bool>> Filter()
    {
        var dateStart = dtpDateStart.Value.Date;
        var dateEnd = dtpDateEnd.Value.Date;
        var description = txtDescription.Text;

        Expression<Func<Entity.Modelos.Flux, bool>> expr = null;

        expr = f => f.DatFlux >= dateStart.Date && f.DatFlux <= dateEnd.Date;

        if (description != String.Empty)
        {
            //add filter
            Expression<Func<Entity.Modelos.Flux, bool>> other = f => f.Description == description;

            var modifier = new MyVisitor();
            expr = (Expression<Func<Entity.Modelos.Flux, bool>>)modifier.Modify((Expression)expr, (LambdaExpression)other);
        }

        return expr;
    }

例

有關更多信息，請查看以下內容

如何：修改表達式樹（C＃和Visual Basic）