[英]Compare elements of list within a list
我有一個這樣的清單:
[[846033, 365, 202], [849432, 276, 140], [821121, 209, 111], [820180, 244, 133], [849401, 971, 572], [848613, 790, 596], [846978, 914, 272]]
小清單的第一個元素是“ idnumber”,其他兩個元素是我要比較的數據。
我想做的事情是:我想刪除大列表中至少兩個數據編號之一小於250的元素。答案應如下所示:
[[849401, 971, 572], [848613, 790, 596], [846978, 914, 272]].
我試圖在for循環中創建一個for循環,但失敗了:
def zonderRuis(sigIdSpot=[[846033, 365, 202], [849432, 276, 140], [821121, 209, 111], [820180, 244, 133], [849401, 971, 572], [848613, 790, 596], [846978, 914, 272]]):
ruisvrij=[]
for i in range(len(sigIdSpot)):
for r in i:
if r[2]>=250 and r[3]>=250:
ruisvrij.append(r)
return ruisvrij
[x for x in data if all(y >= 250 for y in x[1:])]
關於迭代的一點:
for i in range(len(sigIdSpot)):
x = sigIdSpot[i]
print x
# becomes more clear if you do the following:
for x in sigIdSpot:
print x
現在,如果您要調試代碼,則可以打印一些內容以查看代碼的狀態:
def zonderRuis(sigIdSpot=[[846033, 365, 202], [849432, 276, 140], [821121, 209, 111], [820180, 244, 133], [849401, 971, 572], [848613, 790, 596], [846978, 914, 272]]):
ruisvrij=[]
for i in range(len(sigIdSpot)):
print 'i is:', i
for r in i:
print 'r is:', r
if r[2]>=250 and r[3]>=250:
ruisvrij.append(r)
print 'r appended to ruisvrij:', ruisvrij
return ruisvrij
記住,交互式外殼是我們最好的朋友。
In [15]: l = [[846033, 365, 202], [849432, 276, 140], [821121, 209, 111], [820180, 244, 133], [849401, 971, 572], [848613, 790, 596], [846978, 914, 272]]
In [16]: [sub for sub in l if min(sub[1:]) >= 250]
Out[16]: [[849401, 971, 572], [848613, 790, 596], [846978, 914, 272]]
list1 = [[846033, 365, 202], [849432, 276, 140], [821121, 209, 111], [820180, 244, 133], [849401, 971, 572], [848613, 790, 596], [846978, 914, 272]]
list2 = []
for x in list1:
if x[1] > 250 and x[2] > 250:
lijst1.append(x)
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