在WHERE子句和BETWEEN運算符中使用CASE表達式

Question

我試圖根據某些條件從我的表中獲取一些行，如下所示：

SELECT * FROM MyTable WHERE Date BETWEEN 
CASE dayofweek(curdate())
when 1 then curdate() AND adddate(curdate(), interval 6 day)
when 2 then subdate(curdate(), interval 1 day) AND adddate(curdate(), interval 5 day)
when 3 then subdate(curdate(), interval 2 day) AND adddate(curdate(), interval 4 day)
when 4 then subdate(curdate(), interval 3 day) AND adddate(curdate(), interval 3 day)
when 5 then subdate(curdate(), interval 4 day) AND adddate(curdate(), interval 2 day)
when 6 then subdate(curdate(), interval 5 day) AND adddate(curdate(), interval 1 day)
when 7 then subdate(curdate(), interval 6 day) AND curdate()
END

但由於某種原因它不起作用。 它給了我一個語法錯誤。 我應該如何完成這樣的事情？

Answer 1

試試這個，

SELECT * 
FROM MyTable 
WHERE  1 = 
    CASE dayofweek(curdate())
        when 1 then Date BETWEEN curdate() AND adddate(curdate(), interval 6 day)
        when 2 then Date BETWEEN subdate(curdate(), interval 1 day) AND adddate(curdate(), interval 5 day)
        when 3 then Date BETWEEN subdate(curdate(), interval 2 day) AND adddate(curdate(), interval 4 day)
        when 4 then Date BETWEEN subdate(curdate(), interval 3 day) AND adddate(curdate(), interval 3 day)
        when 5 then Date BETWEEN subdate(curdate(), interval 4 day) AND adddate(curdate(), interval 2 day)
        when 6 then Date BETWEEN subdate(curdate(), interval 5 day) AND adddate(curdate(), interval 1 day)
        when 7 then Date BETWEEN subdate(curdate(), interval 6 day) AND curdate()
    END

在這種情況下， CASE()語句將僅返回兩個可能的值： 1和0 。

Answer 2

CASE返回一個值 ，而不是表達式 。 您必須在BETWEEN的每一側重復CASE語句：

SELECT * FROM MyTable
WHERE Date BETWEEN 
  CASE dayofweek(curdate())
    when 1 then curdate()
    when 2 then subdate(curdate(), interval 1 day)
    ... etc
  END
AND -- this is the "AND" for the BETWEEN values
  CASE dayofweek(curdate())
  when 1 then adddate(curdate(), interval 6 day)
  when 2 then adddate(curdate(), interval 5 day)
  ... etc
END