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在WHERE子句和BETWEEN运算符中使用CASE表达式

[英]using CASE expression in the WHERE clause and BETWEEN operator

我试图根据某些条件从我的表中获取一些行,如下所示:

SELECT * FROM MyTable WHERE Date BETWEEN 
CASE dayofweek(curdate())
when 1 then curdate() AND adddate(curdate(), interval 6 day)
when 2 then subdate(curdate(), interval 1 day) AND adddate(curdate(), interval 5 day)
when 3 then subdate(curdate(), interval 2 day) AND adddate(curdate(), interval 4 day)
when 4 then subdate(curdate(), interval 3 day) AND adddate(curdate(), interval 3 day)
when 5 then subdate(curdate(), interval 4 day) AND adddate(curdate(), interval 2 day)
when 6 then subdate(curdate(), interval 5 day) AND adddate(curdate(), interval 1 day)
when 7 then subdate(curdate(), interval 6 day) AND curdate()
END

但由于某种原因它不起作用。 它给了我一个语法错误。 我应该如何完成这样的事情?

试试这个,

SELECT * 
FROM MyTable 
WHERE  1 = 
    CASE dayofweek(curdate())
        when 1 then Date BETWEEN curdate() AND adddate(curdate(), interval 6 day)
        when 2 then Date BETWEEN subdate(curdate(), interval 1 day) AND adddate(curdate(), interval 5 day)
        when 3 then Date BETWEEN subdate(curdate(), interval 2 day) AND adddate(curdate(), interval 4 day)
        when 4 then Date BETWEEN subdate(curdate(), interval 3 day) AND adddate(curdate(), interval 3 day)
        when 5 then Date BETWEEN subdate(curdate(), interval 4 day) AND adddate(curdate(), interval 2 day)
        when 6 then Date BETWEEN subdate(curdate(), interval 5 day) AND adddate(curdate(), interval 1 day)
        when 7 then Date BETWEEN subdate(curdate(), interval 6 day) AND curdate()
    END

在这种情况下, CASE()语句将仅返回两个可能的值: 10

CASE返回一个 ,而不是表达式 您必须在BETWEEN的每一侧重复CASE语句:

SELECT * FROM MyTable
WHERE Date BETWEEN 
  CASE dayofweek(curdate())
    when 1 then curdate()
    when 2 then subdate(curdate(), interval 1 day)
    ... etc
  END
AND -- this is the "AND" for the BETWEEN values
  CASE dayofweek(curdate())
  when 1 then adddate(curdate(), interval 6 day)
  when 2 then adddate(curdate(), interval 5 day)
  ... etc
END

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