簡體   English   中英

隨機選擇具有相同名稱的XML節點

[英]randomly Select XML nodes with same names

我有這個XML文件:

<Main>
<QA>
    <question>What is your favorite color?</question>
    <!--pick random!-->
    <answer>Blue</answer>
    <answer>Red</answer>
    <answer>Green</answer>
    <answer>Yellow</answer>
</QA>

<QA>
    <question>What is your favorite programming language?</question>
    <!--pick random!-->
    <answer>PHP</answer>
    <answer>C#</answer>
    <answer>Java</answer>
    <answer>VB.Net</answer>
</QA>

我想當用戶輸入上面xml文件中指定的問題之一時,程序從節點中選擇一個隨機的答案。 例如,當用戶輸入“您最喜歡的編程語言是什么?”時 在TextBox中,程序必須隨機生成PHP,C#,Java或VB.Net。

這是我的代碼,但不正確:

XmlDocument xml = new XmlDocument();
xml.Load("QA.xml");

XmlNodeList xList = xml.SelectNodes("Main/QA");
foreach (XmlNode xn in xList)
{
    string Question = xn["question"].InnerText;
    if (Question == txtQuestion.Text)
    {
        XmlNodeList answerlist = xml.SelectNodes("Main/QA/answer");
        foreach (XmlNode ans in answerlist)
        {
            Console.WriteLine(ans.InnerText);
        }
    }
}  

輸出:

藍紅綠黃PHP C#Java VB.Net

請幫忙。

使用Linq To Xml,

Random rnd = new Random();
var xDoc = XDocument.Load("QA.xml");

var question = xDoc.Descendants("QA")
                   .First(d => d.Element("question").Value == txtQ.Text);

var answer = question.Elements()
                     .Skip(rnd.Next(0, question.Elements().Count()))
                     .First().Value;

嘗試這個:

XmlDocument xml = new XmlDocument();
xml.Load("QA.xml");

XmlNodeList xList = xml.SelectNodes("Main/QA");
foreach (XmlNode xn in xList)
{
    string Question = xn["question"].InnerText;
    if (Question == txtQuestion.Text)
    {
        XmlNodeList answerlist = xn.SelectNodes("./answer");
        foreach (XmlNode ans in answerlist
            .Cast<XmlNode>()
            .OrderBy(elem => Guid.NewGuid()))
        {
            Console.WriteLine(ans.InnerText);
        }
    }
} 

暫無
暫無

聲明:本站的技術帖子網頁,遵循CC BY-SA 4.0協議,如果您需要轉載,請注明本站網址或者原文地址。任何問題請咨詢:yoyou2525@163.com.

 
粵ICP備18138465號  © 2020-2024 STACKOOM.COM