在Vim之后如何刪除與模式和行匹配的所有行？
[英]How to delete all lines matching a pattern and a line after in Vim?
問題描述
有一個文字
Title of the text
This line contains a word that is matched by the pattern and it should be deleted.
Next line is supposed to be deleted as well.
Loren ipsum dolorem...
This line contains a word that is matched by the pattern and it should be deleted.
And this one should be deleted
The end of the article
如何刪除與第一行匹配的每一對行，例如“此行包含一個單詞...”以及該行之后的行。 結果將是：
Title of the text
Loren ipsum dolorem...
The end of the article
5 個解決方案
解決方案1
45 已采納 2013-04-25 19:27:35
您可以使用
:g/word/normal 2dd
這將查找word的所有實例，然后在其后執行命令。 在這種情況下，它在正常模式下執行2dd
解決方案2
20 2013-04-25 19:27:33
解決方案3
4 2013-04-25 19:27:58
您可以使用:g[lobal]命令：
:g/This line/norm 3dd
解決方案4
2 2013-04-25 20:48:00
另一種方式：g
:g/word/norm dj
解決方案5
0 2015-03-20 04:44:44
你可能想試試這個：
:g/your pattern go here/d
vim：找到一個模式，跳過一個單詞，然后在所有匹配的行中附加一些內容
[英]vim : Find a pattern, skip a word and append something in all matching lines
刪除與模式匹配的行和所有后續行，直到第二個模式
[英]Delete line that matches pattern and all subsequent lines until second pattern
SED：在模式匹配后刪除行，同時跳過幾行，然后刪除模式行
[英]SED: delete lines after pattern match while skipping a few lines, then delete the pattern line
Vim：如果 submatch(1) 為空，則刪除與模式匹配的文本
[英]Vim: Delete the text matching a pattern IF submatch(1) is empty
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