在Vim之后如何删除与模式和行匹配的所有行？

Question

有一个文字

Title of the text

This line contains a word that is matched by the pattern and it should be deleted.
Next line is supposed to be deleted as well.

Loren ipsum dolorem...

This line contains a word that is matched by the pattern and it should be deleted.
And this one should be deleted

The end of the article

如何删除与第一行匹配的每一对行，例如“此行包含一个单词...”以及该行之后的行。 结果将是：

Title of the text

Loren ipsum dolorem...

The end of the article

Answer 1

您可以使用

:g/word/normal 2dd

这将查找word的所有实例，然后在其后执行命令。 在这种情况下，它在正常模式下执行2dd

Answer 2

使用:g[lobal]使用带有,+1范围的d[elete]命令删除匹配的行和下一行：

:g/word/,+1d

• :global
• :delete
• 命令范围

Answer 3

您可以使用:g[lobal]命令：

:g/This line/norm 3dd

Answer 4

另一种方式：g

:g/word/norm dj

Answer 5

你可能想试试这个：

:g/your pattern go here/d