.split（“，”）分隔字符串的每個字符

Question

在程序的某個點上，我要求它接受用戶的文本輸入並根據其逗號分隔文本，然后單擊",".join再次",".join其",".join到txt文件中。 這個想法是要有一個列表，其中包含所有用逗號分隔的信息。

問題是，顯然，當我",".join時，它用逗號分隔每個單個字符，因此，如果我有字符串info1,info2它將分開，從而得到info1 | info2 info1 | info2 ，但是，當再次將其重新加入時，它會像i,n,f,o,1,,,i,n,f,o,2,這是非常令人困惑的，因為它是從txt文件返回的文本以便稍后在程序中向用戶顯示。 有人可以幫我嗎？

        categories = open('c:/digitalLibrary/' + connectedUser + '/category.txt', 'a')
        categories.write(BookCategory + '\n')
        categories.close()
        categories = open('c:/digitalLibrary/' + connectedUser + '/category.txt', 'r')
        categoryList = categories.readlines()
        categories.close()

            for category in BookCategory.split(','):
                for readCategory in lastReadCategoriesList:
                    if readCategory.split(',')[0] == category.strip():
                        count = int(readCategory.split(',')[1])
                        count += 1
                        i = lastReadCategoriesList.index(readCategory)
                        lastReadCategoriesList[i] = category.strip() + "," + str(count).strip()
                        isThere = True
                if not isThere:
                    lastReadCategoriesList.append(category.strip() + ",1")
                isThere = False

            lastReadCategories = open('c:/digitalLibrary/' + connectedUser + '/lastReadCategories.txt', 'w')
            for category in lastReadCategoriesList:
                if category.split(',')[0] != "" and category != "":
                    lastReadCategories.write(category + '\n')
            lastReadCategories.close()

        global finalList

        finalList.append({"Title":BookTitle + '\n', "Author":AuthorName + '\n', "Borrowed":IsBorrowed + '\n', "Read":readList[len(readList)-1], "BeingRead":readingList[len(readingList)-1], "Category":BookCategory + '\n', "Collection":BookCollection + '\n', "Comments":BookComments + '\n'})

        finalList = sorted(finalList, key=itemgetter('Title'))

        for i in range(len(finalList)):
            categoryList[i] = finalList[i]["Category"]
            toAppend = (str(i + 1) + ".").ljust(7) + finalList[i]['Title'].strip()
            s.append(toAppend)

        categories = open('c:/digitalLibrary/' + connectedUser + '/category.txt', 'w')
        for i in range(len(categoryList)):
            categories.write(",".join(categoryList[i]))
        categories.close()

Answer 1

您應該傳遞''.join()一個列表，而是傳遞一個字符串。

字符串也是序列，所以''.join()會將每個字符都視為一個單獨的元素：

>>> ','.join('Hello world')
'H,e,l,l,o, ,w,o,r,l,d'
>>> ','.join(['Hello', 'world'])
'Hello,world'