.split（“，”）分隔字符串的每个字符

Question

在程序的某个点上，我要求它接受用户的文本输入并根据其逗号分隔文本，然后单击",".join再次",".join其",".join到txt文件中。 这个想法是要有一个列表，其中包含所有用逗号分隔的信息。

问题是，显然，当我",".join时，它用逗号分隔每个单个字符，因此，如果我有字符串info1,info2它将分开，从而得到info1 | info2 info1 | info2 ，但是，当再次将其重新加入时，它会像i,n,f,o,1,,,i,n,f,o,2,这是非常令人困惑的，因为它是从txt文件返回的文本以便稍后在程序中向用户显示。 有人可以帮我吗？

        categories = open('c:/digitalLibrary/' + connectedUser + '/category.txt', 'a')
        categories.write(BookCategory + '\n')
        categories.close()
        categories = open('c:/digitalLibrary/' + connectedUser + '/category.txt', 'r')
        categoryList = categories.readlines()
        categories.close()

            for category in BookCategory.split(','):
                for readCategory in lastReadCategoriesList:
                    if readCategory.split(',')[0] == category.strip():
                        count = int(readCategory.split(',')[1])
                        count += 1
                        i = lastReadCategoriesList.index(readCategory)
                        lastReadCategoriesList[i] = category.strip() + "," + str(count).strip()
                        isThere = True
                if not isThere:
                    lastReadCategoriesList.append(category.strip() + ",1")
                isThere = False

            lastReadCategories = open('c:/digitalLibrary/' + connectedUser + '/lastReadCategories.txt', 'w')
            for category in lastReadCategoriesList:
                if category.split(',')[0] != "" and category != "":
                    lastReadCategories.write(category + '\n')
            lastReadCategories.close()

        global finalList

        finalList.append({"Title":BookTitle + '\n', "Author":AuthorName + '\n', "Borrowed":IsBorrowed + '\n', "Read":readList[len(readList)-1], "BeingRead":readingList[len(readingList)-1], "Category":BookCategory + '\n', "Collection":BookCollection + '\n', "Comments":BookComments + '\n'})

        finalList = sorted(finalList, key=itemgetter('Title'))

        for i in range(len(finalList)):
            categoryList[i] = finalList[i]["Category"]
            toAppend = (str(i + 1) + ".").ljust(7) + finalList[i]['Title'].strip()
            s.append(toAppend)

        categories = open('c:/digitalLibrary/' + connectedUser + '/category.txt', 'w')
        for i in range(len(categoryList)):
            categories.write(",".join(categoryList[i]))
        categories.close()

Answer 1

您应该传递''.join()一个列表，而是传递一个字符串。

字符串也是序列，所以''.join()会将每个字符都视为一个单独的元素：

>>> ','.join('Hello world')
'H,e,l,l,o, ,w,o,r,l,d'
>>> ','.join(['Hello', 'world'])
'Hello,world'