PyQt GUI控件從另一個線程的訪問

Question

我正在嘗試在python中創建客戶端服務器應用程序。 當服務器關閉時，我希望客戶端的GUI位於單獨的線程上關閉，但是應用程序因Xlib錯誤而崩潰：錯誤的實現...我已經搜索過，似乎是從其他線程訪問GUI接口。 我該怎么辦？其他線程的python gui訪問

Answer 1

這可能對您有幫助。

from PyQt4 import QtGui as gui
from PyQt4 import QtCore as core

import sys
import time


class ServerThread(core.QThread):
    def __init__(self, parent=None):
        core.QThread.__init__(self)

    def start_server(self):
        for i in range(1,6):
            time.sleep(1)
            self.emit(core.SIGNAL("dosomething(QString)"), str(i))

    def run(self):
        self.start_server()


class MainApp(gui.QWidget):
    def __init__(self, parent=None):
        super(MainApp,self).__init__(parent)

        self.label = gui.QLabel("hello world!!")

        layout = gui.QHBoxLayout(self)
        layout.addWidget(self.label)

        self.thread = ServerThread()
        self.thread.start()

        self.connect(self.thread, core.SIGNAL("dosomething(QString)"), self.doing)

    def doing(self, i):
        self.label.setText(i)
        if i == "5":
            self.destroy(self, destroyWindow =True, destroySubWindows = True)
            sys.exit()


app = gui.QApplication(sys.argv)
form = MainApp()
form.show()
app.exec_()