[英]PyQt GUI control access from another thread
我正在尝试在python中创建客户端服务器应用程序。 当服务器关闭时,我希望客户端的GUI位于单独的线程上关闭,但是应用程序因Xlib错误而崩溃:错误的实现...我已经搜索过,似乎是从其他线程访问GUI接口。 我该怎么办?其他线程的python gui访问
这可能对您有帮助。
from PyQt4 import QtGui as gui
from PyQt4 import QtCore as core
import sys
import time
class ServerThread(core.QThread):
def __init__(self, parent=None):
core.QThread.__init__(self)
def start_server(self):
for i in range(1,6):
time.sleep(1)
self.emit(core.SIGNAL("dosomething(QString)"), str(i))
def run(self):
self.start_server()
class MainApp(gui.QWidget):
def __init__(self, parent=None):
super(MainApp,self).__init__(parent)
self.label = gui.QLabel("hello world!!")
layout = gui.QHBoxLayout(self)
layout.addWidget(self.label)
self.thread = ServerThread()
self.thread.start()
self.connect(self.thread, core.SIGNAL("dosomething(QString)"), self.doing)
def doing(self, i):
self.label.setText(i)
if i == "5":
self.destroy(self, destroyWindow =True, destroySubWindows = True)
sys.exit()
app = gui.QApplication(sys.argv)
form = MainApp()
form.show()
app.exec_()
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