[英]How to remove one NSArray's objects from another NSMutableArray?
[英]Remove duplicates from NSArray of Custom Objects also compare and edit same
我有兩個NSMutableArrays
。 每個對象都包含一個自定義單詞對象。 自定義詞有2個屬性,文本和頻率。 現在,我想以一種方式組合這兩個arrays
,如果這兩個數組中包含相同的文本,則它應該比較這兩個文本的頻率並選擇兩者的最高頻率。 並且它也應該從array
刪除重復項。 我為此嘗試了所有邏輯,但無法做到這一點。 任何機構都可以在邏輯上幫助我。 遵循代碼。 但是它也應該刪除重復項。
for (int i = 0; i < [array count]; i++) {
for (int j = 0; j < [array count]; j++) {
if ([[[array objectAtIndex:i]firstWord] isEqualToString:[[array objectAtIndex:j] firstWord]]) {
if ([[array objectAtIndex:i] frequency] < [[array objectAtIndex:j] frequency]) {
CustomWordFrequency *word = [array objectAtIndex:i];
word.frequency = [[array objectAtIndex:j] frequency];
[array replaceObjectAtIndex:i withObject:word];
}
}
}
}
遍歷數組
一種。 查看數組中的下一項。 如果文本與當前單詞相同,則將其從數組中刪除。 如果不同,請繼續循環。
NSArray *combined = [firstArray arrayByAddingObjectsFromArray:secondArray]; [combined sortUsingComparator:^(id firstObject, id secondObject) { NSComparisonResult *result = [firstObject.text compare:secondObject.text]; if (result == NSOrderedAscending) return NSOrderedAscending; if (result == NSOrderedDescending) return NSOrderedDescending; if (result == NSOrderedSame) { result = [firstObject.frequency compare:secondObject.frequency]; if (result == NSOrderedAscending) return NSOrderedDescending; if (result == NSOrderedDescending) return NSOrderedAscending; if (result == NSOrderedSame) return NSOrderedSame; } }]; for (int i = 0; i < [combined count] - 2; ++i) { CustomWordFrequency *word = [combined objectAtIndex:i]; int j = i + 1; while ([word.text compare:[combined objectAtIndex:j].text == NSOrderedSame) { [combined removeObjectAtIndex:j]; j++; if (j == [combined count]) {break;} } if (i >= [combined count] - 2) {break;} // the count keeps changing so check here }
NSMutableArray *combinedArray = [[NSMutableArray alloc] init];
BOOL flagForMatchFound = FALSE;
for(CustomWordFrequency *firstWord in firstArray)
{
flagForMatchFound = FALSE;
for(CustomWordFrequency *secondWord in secondArray)
{
if([firstWord.firstWord isEqualToString:secondWord.firstWord])
{
if(firstWord.frequency >= secondWord.frequency)
{
[combinedArray addObject:firstWord];
flagForMatchFound = TRUE;
}
else
[combinedArray addObject:secondWord];
}
else
{
if(!flagForMatchFound)
[combinedArray addObject:secondWord];
}
}
}
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