[英]How to remove one NSArray's objects from another NSMutableArray?
[英]Remove duplicates from NSArray of Custom Objects also compare and edit same
我有两个NSMutableArrays
。 每个对象都包含一个自定义单词对象。 自定义词有2个属性,文本和频率。 现在,我想以一种方式组合这两个arrays
,如果这两个数组中包含相同的文本,则它应该比较这两个文本的频率并选择两者的最高频率。 并且它也应该从array
删除重复项。 我为此尝试了所有逻辑,但无法做到这一点。 任何机构都可以在逻辑上帮助我。 遵循代码。 但是它也应该删除重复项。
for (int i = 0; i < [array count]; i++) {
for (int j = 0; j < [array count]; j++) {
if ([[[array objectAtIndex:i]firstWord] isEqualToString:[[array objectAtIndex:j] firstWord]]) {
if ([[array objectAtIndex:i] frequency] < [[array objectAtIndex:j] frequency]) {
CustomWordFrequency *word = [array objectAtIndex:i];
word.frequency = [[array objectAtIndex:j] frequency];
[array replaceObjectAtIndex:i withObject:word];
}
}
}
}
遍历数组
一种。 查看数组中的下一项。 如果文本与当前单词相同,则将其从数组中删除。 如果不同,请继续循环。
NSArray *combined = [firstArray arrayByAddingObjectsFromArray:secondArray]; [combined sortUsingComparator:^(id firstObject, id secondObject) { NSComparisonResult *result = [firstObject.text compare:secondObject.text]; if (result == NSOrderedAscending) return NSOrderedAscending; if (result == NSOrderedDescending) return NSOrderedDescending; if (result == NSOrderedSame) { result = [firstObject.frequency compare:secondObject.frequency]; if (result == NSOrderedAscending) return NSOrderedDescending; if (result == NSOrderedDescending) return NSOrderedAscending; if (result == NSOrderedSame) return NSOrderedSame; } }]; for (int i = 0; i < [combined count] - 2; ++i) { CustomWordFrequency *word = [combined objectAtIndex:i]; int j = i + 1; while ([word.text compare:[combined objectAtIndex:j].text == NSOrderedSame) { [combined removeObjectAtIndex:j]; j++; if (j == [combined count]) {break;} } if (i >= [combined count] - 2) {break;} // the count keeps changing so check here }
NSMutableArray *combinedArray = [[NSMutableArray alloc] init];
BOOL flagForMatchFound = FALSE;
for(CustomWordFrequency *firstWord in firstArray)
{
flagForMatchFound = FALSE;
for(CustomWordFrequency *secondWord in secondArray)
{
if([firstWord.firstWord isEqualToString:secondWord.firstWord])
{
if(firstWord.frequency >= secondWord.frequency)
{
[combinedArray addObject:firstWord];
flagForMatchFound = TRUE;
}
else
[combinedArray addObject:secondWord];
}
else
{
if(!flagForMatchFound)
[combinedArray addObject:secondWord];
}
}
}
声明:本站的技术帖子网页,遵循CC BY-SA 4.0协议,如果您需要转载,请注明本站网址或者原文地址。任何问题请咨询:yoyou2525@163.com.