MySQL - 使用關系表加入

Question

我有三張桌子

USER
---------------------------------------
id | uid | first_name | last_name | ...
---------------------------------------
0  | 95  | ...        | ...       | ...   
1  | 100 | ...        | ...       | ...     
2  | 120 | ...        | ...       | ...
3  | 130 | ...        | ...       | ...

NEWS_mm
------------------------
uid_local | uid_foreign 
------------------------
40        | 90        
40        | 100 
50        | 120 
50        | 130

NEWS
-------------------------------
id | uid  | title | image | ...
-------------------------------
0  | 40   | ...   | ...   | ...    
1  | 50   | ...   | ...   | ...
2  | 60   | ...   | ...   | ...

現在我只想從表“USER”中選擇所有用戶，其中包含來自表“NEWS”的新聞ID 50。 NEWS_mm具有來自“NEWS”的新聞id（id_local）和來自“USER”的用戶id（id_foreign）

SELECT USER.*, NEWS_MM.*, NEWS.*
FROM USER
    JOIN NEWS_MM
        ON NEWS_MM.uid_foreign = USER.uid
    JOIN NEWS
        ON NEWS_MM.uid_local = NEWS_MM.uid_local
WHERE NEWS.uid = 50 

Answer 1

你是在正確的行，但你加入NEWS_MM = NEWS_MM的新聞我懷疑你想加入如下：

SELECT USER.*, NEWS_MM.*, NEWS.*
FROM USER
JOIN NEWS_MM
    ON NEWS_MM.uid_foreign = USER.uid
JOIN NEWS
    ON NEWS_MM.uid_local = NEWS.uid
WHERE NEWS.uid = 50  

另請注意，您知道NEWS_MM.uid_local的值與NEWS.uid相同，因此如果您只想要USER表中的數據，那么您根本不需要第二次連接，這樣可以提供更好的性能

SELECT 
  NEWS_MM.uid_local, 
  USER.* 
FROM USER
  JOIN NEWS_MM
    ON NEWS_MM.uid_foreign = USER.uid
WHERE NEWS_MM.uid_local = 50