mysql關系表

Question

我有4張桌子，如下所示，

MariaDB [nava_hotel]> desc transaksi;
+----------------+-------------+------+-----+---------+-------+
| Field          | Type        | Null | Key | Default | Extra |
+----------------+-------------+------+-----+---------+-------+
| kode_transaksi | varchar(10) | NO   | PRI | NULL    |       |
| kode_pemesanan | varchar(10) | YES  |     | NULL    |       |
| lama_menginap  | int(3)      | YES  |     | NULL    |       |
| total          | bigint(20)  | YES  |     | NULL    |       |
+----------------+-------------+------+-----+---------+-------+

MariaDB [nava_hotel]> desc pemesanan;
+----------------+-------------+------+-----+---------+-------+
| Field          | Type        | Null | Key | Default | Extra |
+----------------+-------------+------+-----+---------+-------+
| kode_pemesanan | varchar(10) | NO   | PRI | NULL    |       |
| kode_tamu      | varchar(10) | YES  |     | NULL    |       |
| kode_kamar     | varchar(10) | YES  |     | NULL    |       |
| tgl_checkin    | datetime    | YES  |     | NULL    |       |
| tgl_checkout   | datetime    | YES  |     | NULL    |       |
+----------------+-------------+------+-----+---------+-------+

MariaDB [nava_hotel]> desc tamu;
+-----------+-------------+------+-----+---------+-------+
| Field     | Type        | Null | Key | Default | Extra |
+-----------+-------------+------+-----+---------+-------+
| kode_tamu | varchar(10) | NO   | PRI | NULL    |       |
| nama      | varchar(30) | YES  |     | NULL    |       |
| alamat    | text        | YES  |     | NULL    |       |
| telepon   | varchar(15) | YES  |     | NULL    |       |
| email     | varchar(20) | YES  |     | NULL    |       |
+-----------+-------------+------+-----+---------+-------+

MariaDB [nava_hotel]> desc kamar;
+-------------+-------------+------+-----+---------+-------+
| Field       | Type        | Null | Key | Default | Extra |
+-------------+-------------+------+-----+---------+-------+
| kode_kamar  | varchar(10) | NO   | PRI | NULL    |       |
| jenis_kamar | varchar(20) | YES  |     | NULL    |       |
| fasilitas   | text        | YES  |     | NULL    |       |
| harga       | bigint(20)  | YES  |     | NULL    |       |
+-------------+-------------+------+-----+---------+-------+

如何通過連接四個表來編寫新查詢並獲得與以下相同的結果：

kode_transaksi,kode_pemesanan,kode_kamar,jenis_kamar,kode_tamu,nama

我是數據庫新手，需要幫助。 提前致謝

Answer 1

可以使用以下JOIN查詢：

select t.kode_transaksi,p.kode_pemesanan,p.kode_kamar,k.jenis_kamar,p.kode_tamu,m.nama
  from pemesanan p
       inner join transaksi t on ( t.kode_pemesanan = p.kode_pemesanan )
       inner join tamu m on ( m.kode_tamu = p.kode_tamu )
       inner join kamar k on ( k.kode_kamar = p.kode_kamar );