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jQuery AJAX調用觸發錯誤函數

[英]jQuery AJAX Call Triggers Error Function

我在代碼中使用了這個ajax調用,但是每次都會觸發錯誤函數。 有人知道為什么會這樣嗎?

$.ajax({
    type:'GET',
    url: 'https://s3.amazonaws.com/GSTArticles/GoogleMaps/Landmarks.xml',
    datatype: 'xml',
    success: function(xml){
        console.log(xml);
    },
    error: function(err){
        alert("ERROR!");
    }
});

據我了解,語法看起來是正確的。 有人可以幫我看看為什么會觸發錯誤,而不是將xml放入控制台嗎? 謝謝。

我還在控制台中看到了這一點: XMLHttpRequest cannot load https://s3.amazonaws.com/GSTArticles/GoogleMaps/Landmarks.xml. Origin null is not allowed by Access-Control-Allow-Origin. XMLHttpRequest cannot load https://s3.amazonaws.com/GSTArticles/GoogleMaps/Landmarks.xml. Origin null is not allowed by Access-Control-Allow-Origin.

您需要使用jsonp來使用ajax進行跨域請求-這意味着您無法使用jQuery的ajax方法來請求XML。 這是其他相關問題。

Jquery的跨域問題

如何在jQuery中解析XML跨域?

您可以使用Yahoo API庫(YQL)來獲取xml

來自http://www.cypressnorth.com/blog/programming/cross-domain-ajax-request-with-xml-response-for-iefirefoxchrome-safari-jquery/

// Accepts a url and a callback function to run.
function requestCrossDomain(site, callback) {

    // If no url was passed, exit.
    if (!site) {
        alert('No site was passed.');
        return false;
    } 
    // Take the provided url, and add it to a YQL query. Make sure you encode it!
    var yql = 'http://query.yahooapis.com/v1/public/yql?q=' + encodeURIComponent('select * from xml where url="' + site + '"') + '&format=xml&callback=?';

    // Request that YSQL string, and run a callback function.
    // Pass a defined function to prevent cache-busting.
    $.getJSON(yql, cbFunc);

    function cbFunc(data) {
        // If we have something to work with...
        if (data.results[0]) {
            if (typeof callback === 'function') {
                callback(data);
            }
        }
        // Else, Maybe we requested a site that doesn't exist, and nothing returned.
        else throw new Error('Nothing returned from getJSON.');
    }
}
function xmlSuccess(data){
    console.log(data.results[0]);
}
requestCrossDomain('https://s3.amazonaws.com/GSTArticles/GoogleMaps/Landmarks.xml',xmlSuccess);

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