[英]How to delete a node in XML, if I have attribute ID and value if node under that album ID
<Albums>
<Album ID="ankit">
<AlbumName>Jaipur Tour</AlbumName>
<AlbumName>Shimla Tour</AlbumName>
<AlbumName>Andaman Tour</AlbumName>
<AlbumName>France Tour</AlbumName>
</Album>
<Album ID="amit">
<AlbumName>Goa Tour</AlbumName>
<AlbumName>China Tour</AlbumName>
<AlbumName>Panama Tour</AlbumName> // delete this node
<AlbumName>Europe Tour</AlbumName>
</Album>
</Albums>
要從提供了用戶名並在該用戶名下提供了專輯名稱的album.xml中刪除專輯
var qryAlbum = from element in loadAlbum.Descendants("Album")
where (string)element.Attribute("ID") == UIDLabel.Text
select element;
qryAlbum.Descendants("Album").Elements("AlbumName").Where(x => x.Value == albumSelected).Remove();
loadAlbum.Save(@"D:\PhotoFrame\Album.xml");
您需要選擇要刪除的元素。
var element = loadAlbum.Descendants("AlbumName")
.Where(x => x.Value == "Panama Tour"
&& x.Parent.Attribute("ID").Value == "amit" )
.FirstOrDefault();
if (element != null)
{
element.Remove();
loadAlbum.Save(@"file.xml");
}
編輯:替換text
if (element != null)
{
element.Value = "New Value";
loadAlbum.Save(@"file.xml");
}
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