[英]C# pass path in argument
我正在將cmd作為C#中的進程啟動,我想在參數中傳遞文件路徑。 怎么做?
Process CommandStart = new Process();
CommandStart.StartInfo.UseShellExecute = true;
CommandStart.StartInfo.RedirectStandardOutput = false;
CommandStart.StartInfo.WindowStyle = ProcessWindowStyle.Hidden;
CommandStart.StartInfo.FileName = "cmd";
CommandStart.StartInfo.Arguments = "(here i want to put a file path to a executable) -arg bla -anotherArg blabla < (and here I want to put another file path)";
CommandStart.Start();
CommandStart.WaitForExit();
CommandStart.Close();
編輯:
Process MySQLDump = new Process();
MySQLDump.StartInfo.UseShellExecute = true;
MySQLDump.StartInfo.RedirectStandardOutput = false;
MySQLDump.StartInfo.WindowStyle = ProcessWindowStyle.Hidden;
MySQLDump.StartInfo.FileName = "cmd";
MySQLDump.StartInfo.Arguments = "/c \"\"" + MySQLDumpExecutablePath + "\" -u " + SQLActions.MySQLUser + " -p" + SQLActions.MySQLPassword + " -h " + SQLActions.MySQLServer + " --port=" + SQLActions.MySQLPort + " " + SQLActions.MySQLDatabase + " \" > " + SQLActions.MySQLDatabase + "_date_" + date + ".sql";
MySQLDump.Start();
MySQLDump.WaitForExit();
MySQLDump.Close();
您需要將文件路徑放在雙引號中,並使用逐字字符串文字( @
)作為SLaks提及。
CommandStart.StartInfo.Arguments = @"""C:\MyPath\file.exe"" -arg bla -anotherArg";
OpenFileDialog的示例
using(OpenFileDialog ofd = new OpenFileDialog())
{
if (ofd.ShowDialog() == System.Windows.Forms.DialogResult.OK)
{
string filePath = "\"" + ofd.FileName + "\"";
//..set up process..
CommandStart.StartInfo.Arguments = filePath + " -arg bla -anotherArg";
}
}
更新以發表評論
您可以使用String.Format
格式化字符串。
string finalPath = String.Format("\"{0}{1}_date_{2}.sql\"", AppDomain.CurrentDomain.BaseDirectory, SQLActions.MySQLDatabase, date);
然后將finalPath
傳遞到參數中。
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