[英]Getting response From Ajax call
當嘗試從使用普通香草javascript構建的ajax調用中獲取responseText時,Firebug似乎看到了請求,但無法獲得對responseText的引用。
這是功能代碼
function getAjaxResponse(){
var ajaxObj = getAjaxObj();
ajaxObj.open('get', 'responsePage.php', true);
ajaxObj.onReadyStateChanged = function(){
if(ajaxObj.readyState == 4
&& ajaxObj.status == 200){
//no functions are getting fired in here
//this does not get logged to console
console.log(ajaxObj.responseText);
//neither does this
console.log(2);
}
};
ajaxObj.send(null);
//this does gets logged to console
console.log(1);
}
Ajax對象的功能
function getAjaxObj(){
var req;
if(window.XMLHttpRequest){
try{
req = new XMLHttpRequest();
} catch(e){
req = false;
} finally {
return req;
}
} else {
if(window.ActiveXObject){
try{
req = new ActiveXObject("Msxml2.XMLHTTP");
} catch(e){
try{
req = new ActiveXObject("Msxml.XMLHTTP");
} catch(e){
req = false;
} finally {
return req;
}
}
}
}
}
這也是螢火蟲的景色
如何獲得對ajax調用響應的引用?
OnReadyStateChanged
需要為onreadystatechange
。 JavaScript區分大小寫。
ajaxObj.onReadyStateChanged
: onreadystatechange
應該全部為小寫(並且不帶尾隨的“ d”)
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