[英]SQL group by DATENAME
我正在嘗試獲取特定日期之間一周中每一天的行數。
到目前為止,我有:
SELECT DATENAME(weekday,Date) AS theDay FROM tablename WHERE year(date) = '2013' and (month(date) >= 5 AND month(date) <= 7)
這給了我這樣的東西:
Wednesday
Wednesday
Wednesday
Wednesday
Wednesday
Thursday
Thursday
Friday
Friday
Friday
Friday
Saturday
Saturday
但我希望它像
Wednesday
然后在下一列
5
等等。 我知道這是一個小組成員,但我對SQL的了解不是很好。
SELECT DATENAME(weekday,Date) AS theDay,count(*) NumberOfDays
FROM tablename
WHERE year(date) = '2013' and (month(date) >= 5 AND month(date) <= 7)
group by DATENAME(weekday,Date)
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