DATENAME的SQL组

Question

我正在尝试获取特定日期之间一周中每一天的行数。

到目前为止，我有：

SELECT DATENAME(weekday,Date) AS theDay FROM tablename WHERE year(date) = '2013' and (month(date) >= 5 AND month(date) <= 7)

这给了我这样的东西：

Wednesday
Wednesday
Wednesday
Wednesday
Wednesday
Thursday
Thursday
Friday
Friday
Friday
Friday
Saturday
Saturday

但我希望它像

Wednesday

然后在下一列

5

等等。 我知道这是一个小组成员，但我对SQL的了解不是很好。

Answer 1

SELECT DATENAME(weekday,Date) AS theDay,count(*) NumberOfDays
FROM tablename 
WHERE year(date) = '2013' and (month(date) >= 5 AND month(date) <= 7)
group by DATENAME(weekday,Date)