[英]MySQL user retention and day to day
我試圖弄清楚如何編寫我的SQL查詢來獲得用戶的日常和保留。 考慮在每個比賽回合中都有以下行表round_statistics我有該回合的日期,現在我想:1.知道連續兩天有多少用戶玩過,意思是在星期日和星期一,星期一和星期二玩,但是星期日和星期二不算作連續兩天。 2.用戶保留1-7
保留7是:最近7天有機會玩(意味着他們至少注冊7天)並在7天后有一些活動(記錄)的用戶百分比。
保留時間6-1僅在6-1天相同。
請幫助我找出我的游戲保持力:)您將獲得免費的硬幣來玩..謝謝。
該表的結構為:user_id,round_time
例如,如果我今天玩了3次:
user id | round_time
1000, | '2013-08-10 14:02:53'
1000, | '2013-08-10 14:03:25'
1000, | '2013-08-10 14:04:47'
結果結構為:
date | 2013-08-10 | 2013-07-10
day to day | 10 | 100
retention 7 | 15 | 125
retention 6 | 20 | 210
retention 5 | 30 | 320
retention 4 | 40 | 430
retention 3 | 50 | 540
retention 2 | 60 | 650
retention 1 | 120 | 1620
我的sql沒有解析功能 ,也沒有CTE和數據透視表功能,因此,直接進行所需的查詢不是很直接(而且沒人回答您的問題)。
對於此數據:
create table t ( uid int, rt date);
insert into t values
(99, '2013-08-7 14:02:53' ), <- gap
(99, '2013-08-9 14:02:53' ), <-
(99, '2013-08-10 14:03:25' ),
(1000, '2013-08-7 14:02:53' ),
(1000, '2013-08-8 14:03:25' ),
(1000, '2013-08-9 14:03:25' ),
(1000, '2013-08-10 14:04:47');
這是在給定日期( '2013-08-10 00:00:00' , '%Y-%m-%d')
進行數據透視保留之前的一種方法:
select count( distinct uid ) as n, d, dt from
(
select uid,
'2013-08-10 00:00:00' as d,
G.dt
from
t
inner join
( select 7 as dt union all
select 6 union all select 5 union all
select 4 union all select 3 union all
select 2 union all select 1 union all select 0) G
on DATE_FORMAT( t.rt, '%Y-%m-%d') between
DATE_FORMAT( date_add( '2013-08-10 00:00:00', Interval -1 * G.dt DAY) ,
'%Y-%m-%d')
and
DATE_FORMAT( '2013-08-10 00:00:00' , '%Y-%m-%d')
where DATE_FORMAT(rt , '%Y-%m-%d') <= DATE_FORMAT( '2013-08-10 00:00:00' ,
'%Y-%m-%d')
group by uid, G.dt
having count( distinct DATE_FORMAT( T.rt, '%Y-%m-%d') ) = G.dt + 1
) TT
group by dt
您的預煮數據(DT = 0表示今天訪問,DT = 1表示連續2天,...):
| N | D | DT |
--------------------------------
| 2 | 2013-08-10 00:00:00 | 0 |
| 2 | 2013-08-10 00:00:00 | 1 |
| 1 | 2013-08-10 00:00:00 | 2 |
| 1 | 2013-08-10 00:00:00 | 3 |
這是(對於相同數據):
select count( distinct uid ) as n, d, dt from
(
select uid,
z.zt as d,
G.dt
from
t
cross join
( select distinct DATE_FORMAT( t.rt, '%Y-%m-%d') as zt from t) z
inner join
( select 7 as dt union all
select 6 union all select 5 union all
select 4 union all select 3 union all
select 2 union all select 1 union all select 0) G
on DATE_FORMAT( t.rt, '%Y-%m-%d') between
DATE_FORMAT( date_add( z.zt, Interval -1 * G.dt DAY) ,
'%Y-%m-%d')
and
z.zt
where z.zt <= z.zt
group by uid, G.dt, z.zt
having count( distinct DATE_FORMAT( T.rt, '%Y-%m-%d') ) = G.dt + 1
) TT
group by d,dt
order by d,dt
sqlfiddle的結果: http ://sqlfiddle.com/#!2/c26ec/10/0
| N | D | DT | GROUP_CONCAT( UID) |
--------------------------------------------
| 2 | 2013-08-07 | 0 | 1000,99 |
| 1 | 2013-08-08 | 0 | 1000 |
| 1 | 2013-08-08 | 1 | 1000 |
| 2 | 2013-08-09 | 0 | 1000,99 |
| 1 | 2013-08-09 | 1 | 1000 |
| 1 | 2013-08-09 | 2 | 1000 |
| 2 | 2013-08-10 | 0 | 1000,99 |
| 2 | 2013-08-10 | 1 | 99,1000 |
| 1 | 2013-08-10 | 2 | 1000 |
| 1 | 2013-08-10 | 3 | 1000 |
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