HttpWebRequest和HttpWebResponse顯示舊數據

Question

更新數據后，在調用Web服務時，仍會獲取舊數據。 僅當我注銷該應用程序然后再次登錄時，才會加載新數據。

protected async override void OnNavigatedTo(System.Windows.Navigation.NavigationEventArgs e)
    {
            base.OnNavigatedTo(e);
            parameterValue = this.NavigationContext.QueryString["parameter"];

            Uri UserDetailUrl = new Uri(Constants.WebService.ws_single_user + "?user_id=" + parameterValue);
            HttpWebRequest UserDetailRequest = (HttpWebRequest)HttpWebRequest.Create(UserDetailUrl);
            HttpWebResponse UserDetailResponse = (HttpWebResponse)await UserDetailRequest.GetResponseAsync();
            StreamReader reader = new StreamReader(UserDetailResponse.GetResponseStream());
            string UserDetailString = reader.ReadToEnd();
            reader.Close();
            XDocument XUserDetailDoc = XDocument.Load(new StringReader(UserDetailString));
            if (((XElement)XUserDetailDoc.Element("main")).Element("result").Value == "success")
            {
                txtEmail.Text = ((XElement)XUserDetailDoc.Element("main")).Element("user").Element("email").Value;
                txtFirstName.Text = ((XElement)XUserDetailDoc.Element("main")).Element("user").Element("fname").Value;
                txtLastName.Text = ((XElement)XUserDetailDoc.Element("main")).Element("user").Element("lname").Value;
                txtMobile.Text = ((XElement)XUserDetailDoc.Element("main")).Element("user").Element("mobile").Value;
            }
    }

Windows 8電話應用程序-使用C＃和XAML

GetResponseAsync如下：

  public static Task<HttpWebResponse> GetResponseAsync(this HttpWebRequest request)
    {
        var taskComplete = new TaskCompletionSource<HttpWebResponse>();
        request.BeginGetResponse(asyncResponse =>
        {
            try
            {
                HttpWebRequest responseRequest = (HttpWebRequest)asyncResponse.AsyncState;
                HttpWebResponse someResponse = (HttpWebResponse)responseRequest.EndGetResponse(asyncResponse);
                taskComplete.TrySetResult(someResponse);
            }
            catch (WebException webExc)
            {
                HttpWebResponse failedResponse = (HttpWebResponse)webExc.Response;
                taskComplete.TrySetResult(failedResponse);
            }
        }, request);
        return taskComplete.Task;

Answer 1

似乎HttpWebRequest正在返回緩存的結果。 您有幾種方法可以避免這種情況：

1. 在URL中添加隨機字符串，以便每次都訪問不同的URL（因此www.example.com/page變為www.example.com/page?random=dsa$fds21 ）。
2. 禁用響應緩存，請參閱要添加到OnNavigatedTo新代碼：

--

HttpWebRequest UserDetailRequest = (HttpWebRequest)HttpWebRequest.Create(UserDetailUrl); 
// Define a cache policy for this request only. 
HttpRequestCachePolicy noCachePolicy = new HttpRequestCachePolicy(HttpRequestCacheLevel.NoCacheNoStore);
request.CachePolicy = noCachePolicy;

Answer 2

我面臨着同樣的問題，我通過在服務器端像這樣添加響應頭來解決。

response.setHeader("Cache-Control", "no-cache");

也許這也會對您有幫助。

Answer 3

如果您使用自己的API，請嘗試從那一側關閉緩存。