如何在python beautifulsoup中獲取下一頁鏈接？

Question

我有這個鏈接：

http://www.brothersoft.com/windows/categories.html

我想在div中獲取項目的鏈接。 例：

http://www.brothersoft.com/windows/mp3_audio/midi_tools/

我試過這段代碼：

import urllib
from bs4 import BeautifulSoup

url = 'http://www.brothersoft.com/windows/categories.html'

pageHtml = urllib.urlopen(url).read()

soup = BeautifulSoup(pageHtml)

sAll = [div.find('a') for div in soup.findAll('div', attrs={'class':'brLeft'})]

for i in sAll:
    print "http://www.brothersoft.com"+i['href']

但我只得到輸出：

http://www.brothersoft.com/windows/mp3_audio/

如何獲得我需要的輸出？

Answer 1

網址http://www.brothersoft.com/windows/mp3_audio/midi_tools/不在標記<div class='brLeft'> ，因此如果輸出為http://www.brothersoft.com/windows/mp3_audio/ ，那就是正確。

如果您想獲得所需的網址，請進行更改

sAll = [div.find('a') for div in soup.findAll('div', attrs={'class':'brLeft'})]

至

sAll = [div.find('a') for div in soup.findAll('div', attrs={'class':'brRight'})]

更新：

在'midi_tools'中獲取信息的示例

import urllib 
from bs4 import BeautifulSoup

url = 'http://www.brothersoft.com/windows/categories.html'
pageHtml = urllib.urlopen(url).read()
soup = BeautifulSoup(pageHtml)
sAll = [div.find('a') for div in soup.findAll('div', attrs={'class':'brRight'})]
for i in sAll:
    suburl = "http://www.brothersoft.com"+i['href']    #which is a url like 'midi_tools'

    content = urllib.urlopen(suburl).read()
    anosoup = BeautifulSoup(content)
    ablock = anosoup.find('table',{'id':'courseTab'})
    for atr in ablock.findAll('tr',{'class':'border_bot '}):
        print atr.find('dt').a.string      #name
        print "http://www.brothersoft.com" + atr.find('a',{'class':'tabDownload'})['href']   #link