How to get next page link in python beautifulsoup?

Question

I have this link:

http://www.brothersoft.com/windows/categories.html

I am trying to to get the link for the item inside the div. Example:

http://www.brothersoft.com/windows/mp3_audio/midi_tools/

I have tried this code:

import urllib
from bs4 import BeautifulSoup

url = 'http://www.brothersoft.com/windows/categories.html'

pageHtml = urllib.urlopen(url).read()

soup = BeautifulSoup(pageHtml)

sAll = [div.find('a') for div in soup.findAll('div', attrs={'class':'brLeft'})]

for i in sAll:
    print "http://www.brothersoft.com"+i['href']

But I only get output:

http://www.brothersoft.com/windows/mp3_audio/

How can I get output that I needed?

Answer 1

Url http://www.brothersoft.com/windows/mp3_audio/midi_tools/ is not in tag <div class='brLeft'> , so if output is http://www.brothersoft.com/windows/mp3_audio/ , that's correct.

If you want to get the url you want, change

sAll = [div.find('a') for div in soup.findAll('div', attrs={'class':'brLeft'})]

to

sAll = [div.find('a') for div in soup.findAll('div', attrs={'class':'brRight'})]

UPDATE:

an example to get info inside 'midi_tools'

import urllib 
from bs4 import BeautifulSoup

url = 'http://www.brothersoft.com/windows/categories.html'
pageHtml = urllib.urlopen(url).read()
soup = BeautifulSoup(pageHtml)
sAll = [div.find('a') for div in soup.findAll('div', attrs={'class':'brRight'})]
for i in sAll:
    suburl = "http://www.brothersoft.com"+i['href']    #which is a url like 'midi_tools'

    content = urllib.urlopen(suburl).read()
    anosoup = BeautifulSoup(content)
    ablock = anosoup.find('table',{'id':'courseTab'})
    for atr in ablock.findAll('tr',{'class':'border_bot '}):
        print atr.find('dt').a.string      #name
        print "http://www.brothersoft.com" + atr.find('a',{'class':'tabDownload'})['href']   #link