[英]Using CURL to post JSON with PHP variables
我正在嘗試使用ZenDesk的API通過我的網站上的付款表單來創建帳戶。 他們給出的示例代碼是:
curl -v -u {email_address}:{password} https://{subdomain}.zendesk.com/api/v2/users.json \
-H "Content-Type: application/json" -X POST -d '{"user": {"name": "Roger Wilco", "email": "roge@example.org"}}'
由於我需要包括PHP變量,因此我嘗試使用此變量:
$data = array("name" => $entry["1"], "email" => $entry["3"], "role" => "end-user");
$data_string = json_encode($data);
$ch = curl_init('https://xxxx.zendesk.com/api/v2/users.json');
curl_setopt($ch, CURLOPT_USERPWD, "xxxx@example.com:xxxx");
curl_setopt($ch, CURLOPT_CUSTOMREQUEST, "POST");
curl_setopt($ch, CURLOPT_POSTFIELDS, $data_string);
curl_setopt($ch, CURLOPT_RETURNTRANSFER, true);
curl_setopt($ch, CURLOPT_HTTPHEADER, array(
'Content-Type: application/json',
'Content-Length: ' . strlen($data_string))
);
$result = curl_exec($ch);
但是,它不起作用。 就復制第一個代碼段的功能而言,我的代碼是否正確?
我找到了ZenDesk API的另一個示例,並能夠提出以下建議:
<?PHP
define("ZDAPIKEY", "SECRETKEYGOESHERE");
define("ZDUSER", "me@mysite.com");
define("ZDURL", "https://mysite.zendesk.com/api/v2");
/* Note: do not put a trailing slash at the end of v2 */
function curlWrap($url, $json, $action)
{
$ch = curl_init();
curl_setopt($ch, CURLOPT_FOLLOWLOCATION, true);
curl_setopt($ch, CURLOPT_MAXREDIRS, 10 );
curl_setopt($ch, CURLOPT_URL, ZDURL.$url);
curl_setopt($ch, CURLOPT_USERPWD, ZDUSER."/token:".ZDAPIKEY);
switch($action){
case "POST":
curl_setopt($ch, CURLOPT_CUSTOMREQUEST, "POST");
curl_setopt($ch, CURLOPT_POSTFIELDS, $json);
break;
case "GET":
curl_setopt($ch, CURLOPT_CUSTOMREQUEST, "GET");
break;
case "PUT":
curl_setopt($ch, CURLOPT_CUSTOMREQUEST, "PUT");
curl_setopt($ch, CURLOPT_POSTFIELDS, $json);
default:
break;
}
curl_setopt($ch, CURLOPT_HTTPHEADER, array('Content-type: application/json'));
curl_setopt($ch, CURLOPT_USERAGENT, "MozillaXYZ/1.0");
curl_setopt($ch, CURLOPT_RETURNTRANSFER, true);
curl_setopt($ch, CURLOPT_TIMEOUT, 10);
$output = curl_exec($ch);
curl_close($ch);
$decoded = json_decode($output);
return $decoded;
}
$arr = array("z_name"=>$namevariable,
"z_email"=>$emailvariable,
"z_role"=>"end_user",
"z_verified"=>"yes"
);
$create = json_encode(array('user' => array('name' => $arr['z_name'], 'email' => $arr['z_email'], 'role' => $arr['z_role'])), JSON_FORCE_OBJECT);
$data = curlWrap("/users.json", $create, "POST");
var_dump($data);
?>
它似乎正在單獨工作,因此可以回答這里存在的問題。
謝謝大家的幫助 :)
我知道這個問題已經解決了,但是由於我在遇到相同問題時發現了它,並且由於它沒有解決我的問題,所以我認為我會發表自己的想法。 希望它可以幫助其他人。
這是在必須通過PUT提交json數據的情況下對我有用的組合:
curl_setopt($ch, CURLOPT_URL, $url);
curl_setopt($ch, CURLOPT_FRESH_CONNECT, TRUE);
curl_setopt($ch, CURLOPT_RETURNTRANSFER, TRUE);
curl_setopt($ch, CURLOPT_FOLLOWLOCATION, true);
curl_setopt($ch, CURLOPT_TIMEOUT, 90);
curl_setopt($ch, CURLOPT_POSTFIELDS, $json);
curl_setopt($ch, CURLOPT_HTTPHEADER, array('Content-type: application/json', 'Content-Length: ' . strlen($json), 'X-HTTP-Method-Override: PUT'));
請注意,它不需要CURLOPT_CUSTOMREQUEST
或CURLOPT_PUT
因為X-HTTP-Method-Override: PUT
參數可以解決這個問題。
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