[英]Python: Replace one list with another list?
我被卡住了。 我正在網絡上四處移動文件夾,這些文件夾都有唯一的ID到中心位置。 有一些帶有錯別字的文件夾,因此在中心位置與唯一ID不匹配。 我找到了正確的IDS,但是在移動它們之前,我需要重命名這些文件夾。 例如,我創建了一個具有錯誤的唯一ID的excel電子表格,並且在單獨的列中具有正確的ID。 現在,我想使用正確的ID重命名文件夾,然后將這些文件夾轉移到中央位置。 我的代碼很粗糙,因為我想不出一種好方法。 我覺得使用列表是一種方法,但是由於我的代碼正在通過文件夾進行迭代,因此我不確定如何實現此目的
編輯:我認為像這樣可能就是我要找的
例如:在文件夾A中:應將名為12334的文件重命名為1234。然后移動到文件夾1234中的基本目錄中。
這是我的代碼:
import os
import re
import sys
import traceback
import collections
import shutil
movdir = r"C:\Scans"
basedir = r"C:\Links"
subfolder = "\Private Drain Connections"
try:
#Walk through all files in the directory that contains the files to copy
for root, dirs, files in os.walk(movdir):
for filename in files:
#find the name location and name of files
path = os.path.join(root, filename)
#file name and extension
ARN, extension = os.path.splitext(filename)
print ARN
#Location of the corresponding folder in the new directory
link = os.path.join(basedir, ARN)
if not os.path.exists(link):
newname = re.sub(372911000002001,372911000003100,ARN)
newname =re.sub(372809000001400,372909000001400,ARN)
newname =re.sub(372809000001500,372909000001500,ARN)
newname =re.sub(372809000001700,372909000001700,ARN)
newname = re.sub(372812000006800,372912000006800,ARN)
newname =re.sub(372812000006900,372912000006900,ARN)
newname =re.sub(372812000007000,372912000007000,ARN)
newname =re.sub(372812000007100,372912000007100,ARN)
newname =re.sub(372812000007200,372912000007200,ARN)
newname =re.sub(372812000007300,372912000007300,ARN)
newname =re.sub(372812000007400,372912000007400,ARN)
newname =re.sub(372812000007500,372912000007500,ARN)
newname =re.sub(372812000007600,372912000007600,ARN)
newname =re.sub(372812000007700,372912000007700,ARN)
newname =re.sub(372812000011100,372912000011100,ARN)
os.rename(os.path.join(movdir, ARN, extension ),
os.path.join(movdir, newname, extension))
oldpath = os.path.join(root, newname)
print ARN, "to", newname
newpath = basedir + "\\" + newname + subfolder
shutil.copy(oldpath, newpath)
print "Copied"
except:
print ("Error occurred")
由於下面的答案,這是我的最終代碼:
import arcpy
import os
import re
import sys
import traceback
import collections
import shutil
movdir = r"C:\Scans"
basedir = r"C:\Links"
subfolder = "\Private Drain Connections"
import string
l = ['372911000002001',
'372809000001400',
'372809000001500',
'372809000001700',
'37292200000800'
]
l2 = ['372911000003100',
'372909000001400',
'372909000001500',
'372909000001700',
'372922000000800'
]
try:
#Walk through all files in the directory that contains the files to copy
for root, dirs, files in os.walk(movdir):
for filename in files:
#find the name location and name of files
path = os.path.join(root, filename)
#file name and extension
ARN, extension = os.path.splitext(filename)
oldname = str(ARN)
#Location of the corresponding folder in the new directory
link = os.path.join(basedir, ARN)
if not os.path.exists(link):
for ii, jj in zip(l, l2):
newname = re.sub(ii,jj, ARN)
newname = str(newname)
print path
newpath = os.path.join(root, oldname) + extension
print "new name", newpath
os.rename(path, newpath)
print "Renaming"
newpath2 = basedir + "\\" + newname + subfolder
shutil.copy(newpath, newpath2)
print "Copied"
if newname != ARN:
break
else:
continue
except:
print ("Error occurred")
tb = sys.exc_info()[2]
tbinfo = traceback.format_tb(tb)[0]
pymsg = "PYTHON ERRORS:\nTraceback Info:\n" + tbinfo + "\nError Info:\n " + \
str(sys.exc_type)+ ": " + str(sys.exc_value) + "\n"
msgs = "GP ERRORS:\n" + arcpy.GetMessages(2 )+ "\n"
print (pymsg)
print (msgs)
對我而言,方法是將兩個列表都讀入列表對象:
list1 = ["372911000002001", "372809000001400", "372809000001500"]
list2 = ["372911000003100", "372909000001400", "372909000001500"]
for ii, jj in zip(list1, list2):
newname = re.sub(ii,jj,ARN) #re.sub returns ARN if no substitution done
if newname != ARN:
break
一個想法:嘗試將id轉換為字符串。 我的意思是:
newname = re.sub('372911000002001','372911000003100',ARN)
希望能幫助到你!
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