Python：用另一个列表替换一个列表？

Question

我被卡住了。 我正在网络上四处移动文件夹，这些文件夹都有唯一的ID到中心位置。 有一些带有错别字的文件夹，因此在中心位置与唯一ID不匹配。 我找到了正确的IDS，但是在移动它们之前，我需要重命名这些文件夹。 例如，我创建了一个具有错误的唯一ID的excel电子表格，并且在单独的列中具有正确的ID。 现在，我想使用正确的ID重命名文件夹，然后将这些文件夹转移到中央位置。 我的代码很粗糙，因为我想不出一种好方法。 我觉得使用列表是一种方法，但是由于我的代码正在通过文件夹进行迭代，因此我不确定如何实现此目的

编辑：我认为像这样可能就是我要找的

例如：在文件夹A中：应将名为12334的文件重命名为1234。然后移动到文件夹1234中的基本目录中。

这是我的代码：

import os
import re
import sys
import traceback
import collections
import shutil

movdir = r"C:\Scans"
basedir = r"C:\Links"
subfolder = "\Private Drain Connections"

try:
    #Walk through all files in the directory that contains the files to copy
    for root, dirs, files in os.walk(movdir):
        for filename in files:
            #find the name location and name of files
            path = os.path.join(root, filename)

            #file name and extension
            ARN, extension = os.path.splitext(filename)
            print ARN

            #Location of the corresponding folder in the new directory
            link = os.path.join(basedir, ARN)
            if not os.path.exists(link):
                newname = re.sub(372911000002001,372911000003100,ARN)
                newname =re.sub(372809000001400,372909000001400,ARN)
                newname =re.sub(372809000001500,372909000001500,ARN)
                newname =re.sub(372809000001700,372909000001700,ARN)
                newname = re.sub(372812000006800,372912000006800,ARN)
                newname =re.sub(372812000006900,372912000006900,ARN)
                newname =re.sub(372812000007000,372912000007000,ARN)
                newname =re.sub(372812000007100,372912000007100,ARN)
                newname =re.sub(372812000007200,372912000007200,ARN)
                newname =re.sub(372812000007300,372912000007300,ARN)
                newname =re.sub(372812000007400,372912000007400,ARN)
                newname =re.sub(372812000007500,372912000007500,ARN)
                newname =re.sub(372812000007600,372912000007600,ARN)
                newname =re.sub(372812000007700,372912000007700,ARN)
                newname =re.sub(372812000011100,372912000011100,ARN)


                os.rename(os.path.join(movdir, ARN, extension ),
                os.path.join(movdir, newname, extension))
                oldpath = os.path.join(root, newname)
                print ARN, "to", newname
                newpath = basedir + "\\" + newname + subfolder
                shutil.copy(oldpath, newpath)
                print "Copied"

except:
    print ("Error occurred")

由于下面的答案，这是我的最终代码：

import arcpy
import os
import re
import sys
import traceback
import collections
import shutil

movdir = r"C:\Scans"
basedir = r"C:\Links"
subfolder = "\Private Drain Connections"


import string

l = ['372911000002001',
'372809000001400',
'372809000001500',
'372809000001700',
'37292200000800'
]
l2 = ['372911000003100',
'372909000001400',
'372909000001500',
'372909000001700',
'372922000000800'
]

try:
    #Walk through all files in the directory that contains the files to copy
    for root, dirs, files in os.walk(movdir):
        for filename in files:
            #find the name location and name of files
            path = os.path.join(root, filename)

            #file name and extension
            ARN, extension = os.path.splitext(filename)
            oldname = str(ARN)
            #Location of the corresponding folder in the new directory
            link = os.path.join(basedir, ARN)

            if not os.path.exists(link):
                for ii, jj in zip(l, l2):
                    newname = re.sub(ii,jj, ARN)
                    newname = str(newname)
                    print path
                    newpath = os.path.join(root, oldname) +  extension
                    print "new name", newpath
                    os.rename(path, newpath)
                    print "Renaming"
                    newpath2 = basedir + "\\" + newname + subfolder
                    shutil.copy(newpath, newpath2)
                    print "Copied"
                if newname != ARN:
                    break


            else:
                continue

except:
    print ("Error occurred")
    tb = sys.exc_info()[2]
    tbinfo = traceback.format_tb(tb)[0]
    pymsg = "PYTHON ERRORS:\nTraceback Info:\n" + tbinfo + "\nError Info:\n    " + \
        str(sys.exc_type)+ ": " + str(sys.exc_value) + "\n"
    msgs = "GP ERRORS:\n" + arcpy.GetMessages(2 )+ "\n"
    print (pymsg)
    print (msgs)

Answer 1

对我而言，方法是将两个列表都读入列表对象：

list1 = ["372911000002001", "372809000001400", "372809000001500"]
list2 = ["372911000003100", "372909000001400", "372909000001500"]
for ii, jj in zip(list1, list2):
    newname = re.sub(ii,jj,ARN)  #re.sub returns ARN if no substitution done
    if newname != ARN:
       break

Answer 2

一个想法：尝试将id转换为字符串。 我的意思是：

            newname = re.sub('372911000002001','372911000003100',ARN)

希望能帮助到你！