[英]jQuery : update the database with all of the data from the ajax-request
我正在嘗試更新數據庫。
因為我這樣做
來自js代碼
var data = {
"jobid": $('#jobid').val(),
"names": $('#names').val(),
"scripttype": $('#testscripts').val()
};
var msg="";
for(i = 1; i <=4; i++) {
data["Param" + i + "Key"] = $('#key' + i).val();
data["Param" + i + "Value"] = $('#value' + i).val();
}
$.ajax({
type: 'post',
url: "/save",
dataType: "json",
data: data
});
在node.js方面
jobsCollection.update({
_id: id
}, {
$set: {
names: record.names,
script: record.scripttype,
// i dont know what should i place in this part???
// i have to set paramkey and paramValues
}
},
{
upsert: true
},
function (err, result) {
if (!err) return context.sendJson([], 404);
});
在record.names和record.scripttype中獲取正確的值。
I don't know how to set values got from the for loop for updating
request going
Request: /save
{ jobid: '',
names: 'first',
scripttype: 'fow',
Param1Key: '1',
Param1Value: 'oneeeeee',
Param2Key: '2',
Param2Value: 'twoooooooo'
etc........
............
}
由於屬性名稱是動態的,因此您需要使用JavaScript的索引器樣式屬性訪問器,如下所示。
只是基本顛倒過程。 我不確定數據在您調用update
,所以我在下面的示例sourceData
其稱為sourceData
;
// create an object with the well known-property names
var set = {
names : record.names,
script : record.scripttype
};
// now loop through the params and set each one individually
for(i = 1; i <=4; i++) {
var key = "Param" + i + "Key"; // build a key string
set[key] = sourceData[key]; // grab the data and set it
key = "Param" + i + "Value"; // and repeat
set[key] = sourceData[key];
}
然后,將其傳遞給您的更新:
jobsCollection.update({
_id: id
}, {
$set: set // pass the object created above
}, /* etc. */
如果您不知道Params
的數量,您可以:
for .. in
來遍歷所有屬性 對於#2:
for(var key in sourceData) {
// you could filter the property names here if you'd like
// (like if only Params# were important)
set[key] = sourceData[key];
}
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