[英]Python - How to get the first row of each list?
我需要獲取列表的每一行並創建一個新列表。 讓我解釋。
我有這個:
data = [[204.0, u'stock'], [204.0, u'stock']]
我需要改變這個:
column1 = [204.0, 204.0]
colunm2 = [u'stock', u'stock']
關於如何做到這一點的任何線索?
最好的祝福,
使用zip()
:
>>> data = [[204.0, u'stock'], [204.0, u'stock']]
>>> zip(*data)
[(204.0, 204.0), (u'stock', u'stock')]
>>> column1, column2 = zip(*data)
>>> column1
(204.0, 204.0)
>>> column2
(u'stock', u'stock')
或者,來自itertools
izip()
:
>>> from itertools import izip
>>> column1, column2 = izip(*data)
>>> column1
(204.0, 204.0)
>>> column2
(u'stock', u'stock')
一個簡單的列表理解就可以了。
data = [[204.0, u'stock'], [204.0, u'stock']]
column1 = [i[0] for i in data]
column2 = [i[1] for i in data]
>>> column1
[204.0, 204.0]
>>> column2
['stock', 'stock']
可能是,在一行
>>> data = [[204.0, u'stock'], [204.0, u'stock']]
>>> columns = [ [d[k] for d in data] for k in range(2)]
[[204.0, 204.0], ['stock', 'stock']]
>>> columns[0]
[204.0, 204.0]
如果變量的大小可以改變,你可以這樣做:
columns = [ [d[k] for d in data] for k in range(max(map(len,data)))]
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