使用XDocument解析xml-反序列化

Question

我有以下xml

<?xml version="1.0" encoding="UTF-8"?>
<Actions>
    <add order-id="1" symbol="ABC" price="5" quantity="200" />
    <add order-id="2" symbol="123" price="15" quantity="100" />
    <add order-id="3" symbol="ABC" price="5" quantity="300" />
    <add order-id="4" symbol="ABC" price="7" quantity="150" />
    <edit order-id="1" price="7" quantity="200" />
    <remove order-id="4" />
    <add order-id="5" symbol="123" price="17" quantity="300" />
    <add order-id="6" symbol="123" price="12" quantity="150" />
    <edit order-id="3" price="7" quantity="200" />
    <remove order-id="5" />
</Actions>

我需要使用linq將其解析為以下對象結構：

 internal class OrderAction
    {
        private readonly Action action;
        private readonly Order order;
        public Action Action { get { return action; }}
        public Order Order { get { return order; }}

        public OrderAction(Action action,Order order)
        {
            this.action = action;
            this.order = order;
        }
    }

動作是public enum Action { ADD, REMOVE, EDIT }

命令如下：

class Order
    {
        public Order(long orderId, String symbol, int price, int quantity)
        {
            this.orderId = orderId;
            this.symbol = symbol;
            this.price = price;
            this.quantity = quantity;
        }

        public long orderId { get; private set; }
        public String symbol { get; private set; }
        public int price { get; private set; }
        public int quantity { get; private set; }
}

我需要將xml加載到xdocument中，並在文件中找到所有IEnumerable的orderactions。 我如何做到這一點，而不必求助於序列化屬性？

Answer 1

在“編輯和刪除”的情況下，缺少的Order屬性的值應該是什么？我假設string和int的默認值...

這將是LINQ語句（假設您的XDocument稱為doc ）：

var result = doc
    .Root
    .Elements()
    .Select(elem => new OrderAction
            (
                (Action)Enum.Parse(typeof(Action), elem.Name.LocalName.ToUpper()),
                new Order
                (
                    elem.Attributes("order-id").Select(x => long.Parse(x.Value)).FirstOrDefault(),
                    elem.Attributes("symbol").Select(x => x.Value).FirstOrDefault(),
                    elem.Attributes("price").Select(x => int.Parse(x.Value)).FirstOrDefault(),
                    elem.Attributes("quantity").Select(x => int.Parse(x.Value)).FirstOrDefault()
                )
            ));

Answer 2

這是我最好的鏡頭

     XElement doc = XElement.Load("d:\\tst.xml");

     List<OrderAction> lst = doc.Elements().Select(x =>
       new OrderAction(
          (Action)
          Enum.Parse(typeof (Action),
                     x.Name.ToString().ToUpper()),
          new Order(
             long.Parse(x.Attribute("order-id").Value),
             x.Attribute("symbol") != null ? x.Attribute("symbol").Value : "",
             x.Attribute("price") != null ? int.Parse(x.Attribute("price").Value) : 0,
             x.Attribute("quantity") != null ? int.Parse(x.Attribute("quantity").Value): 0))
        ).ToList();

我花了一段時間...我不習慣這么大的linq解析