[英]Key Value Pair List
我有一個包含以下元素的列表:
{[A,1] ; [B,0] ; [C,0] ; [D,2]; [E,0] ; [F,8]}
當Variable = 3 - >我希望返回值為A,D
當變量= 11 - >返回值為A,D,F
當2 - >返回值為D時
等等。
int sum = myList.Sum(x => x.Value)
如何獲得相應的密鑰(A,D,F)?
在這個問題中使用其中一個子集方法
var list = new List<KeyValuePair<string, int>>() {
new KeyValuePair<string, int>("A", 1),
new KeyValuePair<string, int>("B", 0),
new KeyValuePair<string, int>("C", 0),
new KeyValuePair<string, int>("D", 2),
new KeyValuePair<string, int>("E", 8),
};
int input = 11;
var items = SubSets(list).FirstOrDefault(x => x.Sum(y => y.Value)==input);
編輯
一個完整的控制台應用
using System;
using System.Collections.Generic;
using System.Linq;
namespace ConsoleApplication1
{
class Program
{
static void Main(string[] args)
{
var list = new List<KeyValuePair<string, int>>() {
new KeyValuePair<string, int>("A", 1),
new KeyValuePair<string, int>("B", 2),
new KeyValuePair<string, int>("C", 3),
new KeyValuePair<string, int>("D", 4),
new KeyValuePair<string, int>("E", 5),
new KeyValuePair<string, int>("F", 6),
};
int input = 12;
var alternatives = list.SubSets().Where(x => x.Sum(y => y.Value) == input);
foreach (var res in alternatives)
{
Console.WriteLine(String.Join(",", res.Select(x => x.Key)));
}
Console.WriteLine("END");
Console.ReadLine();
}
}
public static class Extenions
{
public static IEnumerable<IEnumerable<T>> SubSets<T>(this IEnumerable<T> enumerable)
{
List<T> list = enumerable.ToList();
ulong upper = (ulong)1 << list.Count;
for (ulong i = 0; i < upper; i++)
{
List<T> l = new List<T>(list.Count);
for (int j = 0; j < sizeof(ulong) * 8; j++)
{
if (((ulong)1 << j) >= upper) break;
if (((i >> j) & 1) == 1)
{
l.Add(list[j]);
}
}
yield return l;
}
}
}
}
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