將UserControl添加到StackPanel時出現ArgumentException

Question

當程序嘗試在DoSend方法中將WordBlock（這是我擴展UserControl的類）添加到StackPanel的內容時，有時（實際上非​​常常見，尤其是當查詢返回多個結果時）拋出ArgumentException，這肯定與它有關線程化（SearchThreadEngine是在第二個線程中運行的方法），但是我在主題上很虛弱，也不知道為什么會發生這種情況。 因此，我將很樂意接受任何幫助。 這是堆棧跟蹤：

{System.ArgumentException: Value does not fall within the expected range.
at MS.Internal.XcpImports.CheckHResult(UInt32 hr)
at MS.Internal.XcpImports.Collection_AddValue[T](PresentationFrameworkCollection`1 collection, CValue value)
at MS.Internal.XcpImports.Collection_AddDependencyObject[T](PresentationFrameworkCollection`1 collection, DependencyObject value)
at System.Windows.PresentationFrameworkCollection`1.AddDependencyObject(DependencyObject value)
at System.Windows.Controls.UIElementCollection.AddInternal(UIElement value)
at System.Windows.PresentationFrameworkCollection`1.Add(T value)
at Dictionary.MainPage.DoSend(IQueryable`1 words, WordContext context)} System.Exception {System.ArgumentException}

public void DoSend(IQueryable<Word> words, WordContext context)
{
    Result.Children.Clear();
    using (context)
    {

        foreach (Word word in words)
        {
            Result.Children.Add(new WordBlock(word));
        }
        waitHandle.Set();
    }

}
public void SearchThreadEngine()
{
    while (!abort)
    {

        if (ToSearch != "")
        {
            string toSearch = ToSearch;
            Thread.Sleep(200);
            if (toSearch != ToSearch)
                continue;
            WordContext wc = new WordContext(WordContext.connectionString);
            ToSearch = "";
            IQueryable<Word> result = (from w in wc.Words where w.Foreign.Equals(toSearch) || w.Foreign.StartsWith(toSearch+" ") select w);
            if(result.Count() == 0)
                result = (from w in wc.Words where w.Foreign.Equals("to "+toSearch) || w.Foreign.StartsWith("to "+toSearch + " ") select w);
            if (result.Count() != 0)
            {
                Result.Dispatcher.BeginInvoke(new SendResult(DoSend), new Object[] { result, wc });
                waitHandle.WaitOne();
            }

        }

    }
    abort = false;
}

Answer 1

Result.Children.Add(new WordBlock(word))

如果該控件same name as another控件具有same name as another這將是您收到的錯誤。 每個成員必須具有唯一的名稱。