[英]tuple of datetime objects in Python
我想編寫一個返回(start,end)元組的函數,其中start是星期一的00:00:00:000000,end是星期日的23:59:59:999999。 start和end是日期時間對象。 沒有提供有關日,月或年的其他信息。 我試過這個功能
def week_start_end(date):
start= date.strptime("00:00:00.000000", "%H:%M:%S.%f")
end = date.strptime("23:59:59.999999", "%H:%M:%S.%f")
return (start,end)
print week_start_end(datetime(2013, 8, 15, 12, 0, 0))
應該返回(datetime(2013,8,11,0,0,0,0),datetime(2013,8,17,23,59,59,999999))
但是該函數返回帶有日期的元組(datetime.datetime(1900,1,1,0,0),datetime.datetime(1900,1,1,23,59,59,999999))
我認為使用datetime.isocalendar是一個不錯的解決方案。 這為您的示例提供了正確的輸出:
import datetime
def iso_year_start(iso_year):
"The gregorian calendar date of the first day of the given ISO year"
fourth_jan = datetime.date(iso_year, 1, 4)
delta = datetime.timedelta(fourth_jan.isoweekday()-1)
return fourth_jan - delta
def iso_to_gregorian(iso_year, iso_week, iso_day):
"Gregorian calendar date for the given ISO year, week and day"
year_start = iso_year_start(iso_year)
return year_start + datetime.timedelta(days=iso_day-1, weeks=iso_week-1)
def week_start_end(date):
year = date.isocalendar()[0]
week = date.isocalendar()[1]
d1 = iso_to_gregorian(year, week, 0)
d2 = iso_to_gregorian(year, week, 6)
d3 = datetime.datetime(d1.year, d1.month, d1.day, 0,0,0,0)
d4 = datetime.datetime(d2.year, d2.month, d2.day, 23,59,59,999999)
return (d3,d4)
舉個例子:
>>> d = datetime.datetime(2013, 8, 15, 12, 0, 0)
>>> print week_start_end(d)
(datetime.datetime(2013, 8, 11, 0, 0), datetime.datetime(2013, 8, 17, 23, 59, 59, 999999))
並且應該幫助您解決問題。
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