間隔添加到日期

Question

我將嘗試解釋其邏輯，並希望有人能夠理解和幫助我。

實際上，我正在數據庫中尋找那些在首次創建帳戶后的前120天內已停止交易，但自上次交易以來120天內處於非活動狀態的人員。

基本上，如果某人進行了120天的交易然后停了下來，而3年后又再次進行交易，我需要他們進入此列表。 因此，使用max(transaction.created_at)是行不通的。

希望我已經正確地解釋了自己。

Answer 1

我假設您有以下類型的日志

table transaction
    user; Timestamp

第一步是對正確的順序進行排序

select t.*, 
@curRow := @curRow + 1 AS row_number 
from transaction t 
JOIN  (SELECT @curRow := 0) r 
order by user, timestamp

結果

user, timestamp, row_id
1       t1           1
1       t1+x         2
...

下一步是加入同一用戶的連續操作

select * from
    (select t.*, 
    @curRow := @curRow + 1 AS row_number 
    from transaction t 
    JOIN  (SELECT @curRow := 0) r 
    order by user, timestamp) a
inner join
    (select t.*, 
    @curRow := @curRow + 1 AS row_number 
    from transaction t 
    JOIN  (SELECT @curRow := 0) r 
    order by user, timestamp)b
on a.user=b.user and a.row_id=b.row_id-1

結果：

user timestamp row user timestamp row
 1      t1      1    1     t1+x    2
 2      t1+x    2    1    t1+x+x2  3
...

現在您只需要按事件之間的時間間隔進行過濾

 select * from
        (select t.*, 
        @curRow := @curRow + 1 AS row_number 
        from transaction t 
        JOIN  (SELECT @curRow := 0) r 
        order by user, timestamp) a
    inner join
        (select t.*, 
        @curRow := @curRow + 1 AS row_number 
        from transaction t 
        JOIN  (SELECT @curRow := 0) r 
        order by user, timestamp)b
    on a.user=b.user and a.row_id=b.row_id+1
WHERE datediff(b.timestamp, a.timestamp)>120

現在，如果您需要在創建acc的頭幾天內發生交易，那么用戶之間的交易中斷時間會超過120天，只需添加where user in(select user from .... where datediff(min(timestamp, creation_Date)<120)或對user_id進行內部聯接以由該子查詢過濾