间隔添加到日期

Question

我将尝试解释其逻辑，并希望有人能够理解和帮助我。

实际上，我正在数据库中寻找那些在首次创建帐户后的前120天内已停止交易，但自上次交易以来120天内处于非活动状态的人员。

基本上，如果某人进行了120天的交易然后停了下来，而3年后又再次进行交易，我需要他们进入此列表。 因此，使用max(transaction.created_at)是行不通的。

希望我已经正确地解释了自己。

Answer 1

我假设您有以下类型的日志

table transaction
    user; Timestamp

第一步是对正确的顺序进行排序

select t.*, 
@curRow := @curRow + 1 AS row_number 
from transaction t 
JOIN  (SELECT @curRow := 0) r 
order by user, timestamp

结果

user, timestamp, row_id
1       t1           1
1       t1+x         2
...

下一步是加入同一用户的连续操作

select * from
    (select t.*, 
    @curRow := @curRow + 1 AS row_number 
    from transaction t 
    JOIN  (SELECT @curRow := 0) r 
    order by user, timestamp) a
inner join
    (select t.*, 
    @curRow := @curRow + 1 AS row_number 
    from transaction t 
    JOIN  (SELECT @curRow := 0) r 
    order by user, timestamp)b
on a.user=b.user and a.row_id=b.row_id-1

结果：

user timestamp row user timestamp row
 1      t1      1    1     t1+x    2
 2      t1+x    2    1    t1+x+x2  3
...

现在您只需要按事件之间的时间间隔进行过滤

 select * from
        (select t.*, 
        @curRow := @curRow + 1 AS row_number 
        from transaction t 
        JOIN  (SELECT @curRow := 0) r 
        order by user, timestamp) a
    inner join
        (select t.*, 
        @curRow := @curRow + 1 AS row_number 
        from transaction t 
        JOIN  (SELECT @curRow := 0) r 
        order by user, timestamp)b
    on a.user=b.user and a.row_id=b.row_id+1
WHERE datediff(b.timestamp, a.timestamp)>120

现在，如果您需要在创建acc的头几天内发生交易，那么用户之间的交易中断时间会超过120天，只需添加where user in(select user from .... where datediff(min(timestamp, creation_Date)<120)或对user_id进行内部联接以由该子查询过滤