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[英]Why was String.StartsWith(char) recently implemented, but not String.Contains(char)?
[英]C# (String.StartsWith && !String.EndsWith && !String.Contains) using a List
我是C#的新手,我遇到了問題。
我有2個List,2個字符串和一個getCombinations(字符串)方法,它返回字符串的所有組合作為List;
我如何驗證一個subjectStrings元素是否沒有StartWith &&!EndsWith &&!包含(或者!StartWith &&!EndsWith && Contains等)每個startswithString,endswithString和containsString的組合?
這是我的代碼在StartWith &&!EndsWith(如果你想看到它運行: http ://ideone.com/y8JZkK)
using System;
using System.Collections.Generic;
using System.Linq;
public class Test
{
public static void Main()
{
List<string> validatedStrings = new List<string>();
List<string> subjectStrings = new List<string>()
{
"con", "cot", "eon", "net", "not", "one", "ten", "toe", "ton",
"cent", "cone", "conn", "cote", "neon", "none", "note", "once", "tone",
"cento", "conte", "nonce", "nonet", "oncet", "tenon", "tonne",
"nocent","concent", "connect"
}; //got a more longer wordlist
string startswithString = "co";
string endswithString = "et";
foreach(var z in subjectStrings)
{
bool valid = false;
foreach(var a in getCombinations(startswithString))
{
foreach(var b in getCombinations(endswithString))
{
if(z.StartsWith(a) && !z.EndsWith(b))
{
valid = true;
break;
}
}
if(valid)
{
break;
}
}
if(valid)
{
validatedStrings.Add(z);
}
}
foreach(var a in validatedStrings)
{
Console.WriteLine(a);
}
Console.WriteLine("\nDone");
}
static List<string> getCombinations(string s)
{
//Code that calculates combinations
return Permutations.Permutate(s);
}
}
public class Permutations
{
private static List<List<string>> allCombinations;
private static void CalculateCombinations(string word, List<string> temp)
{
if (temp.Count == word.Length)
{
List<string> clone = temp.ToList();
if (clone.Distinct().Count() == clone.Count)
{
allCombinations.Add(clone);
}
return;
}
for (int i = 0; i < word.Length; i++)
{
temp.Add(word[i].ToString());
CalculateCombinations(word, temp);
temp.RemoveAt(temp.Count - 1);
}
}
public static List<string> Permutate(string str)
{
allCombinations = new List<List<string>>();
CalculateCombinations(str, new List<string>());
List<string> combinations = new List<string>();
foreach(var a in allCombinations)
{
string c = "";
foreach(var b in a)
{
c+=b;
}
combinations.Add(c);
}
return combinations;
}
}
輸出:
con
cot
cone
conn
cote <<<
conte <<<
concent
connect
Done
if(z.StartsWith(a)&&!z.EndsWith(b))var b可以是“et”和“te”,但cote和conte以“te”結尾,為什么它仍然添加在我的驗證字符串中?
提前致謝。
z.StartsWith(a) && !z.EndsWith(b)
檢查下面的組合
z ="cote"
a ="co"
b ="te"
所以z以“co”開頭而z不以“te”結尾,你的條件傳遞和cote
將添加到列表中
我會嘗試如下
var sw =getCombinations(startswithString);
var ew = getCombinations(endswithString);
var result = subjectStrings.Where(z=>
sw.Any(x=>z.StartsWith(x) &&
!ew.Any(y=>z.EndsWith(y))))
.ToList();
輸出:
con
cot
cone
conn
concent
connect
foreach(var b in getCombinations(endswithString))
{
if(z.StartsWith(a) && !z.EndsWith(b))
{
valid = true;
break;
}
}
只要匹配!z.EndsWith(b)並且您沒有遍歷可用的整個排列列表,就在這里設置有效為true。 因為“cote”不以“et”結尾,所以它是匹配,有效設置為true,代碼中斷。 這就是為什么“cote”被添加到有效字符串列表中的原因。 “conte”的情況也是如此。
你想要做的是:
List<string> startsWithCombination = getCombinations("co");
List<string> endsWithCombination = getCombinations("et");
foreach (var z in subjectStrings)
{
bool isStartMatchFound = startsWithCombination.Any(b => z.StartsWith(b));
if (isStartMatchFound)
{
bool isEndMatchFound = endsWithCombination.Any(b => z.EndsWith(b));
if (!isEndMatchFound)
{
validatedStrings.Add(z);
}
}
}
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