[英]How to determine consecutive date records in sql server
我有這樣的數據結構:
ID Status Date
--- ------ ------------
1 I 2013-10-01
1 A 2013-10-02
1 A 2013-10-03
1 I 2013-10-04
1 I 2013-10-05
1 I 2013-10-06
1 A 2013-10-07
1 I 2013-10-08
我想確定I
連續有多少個狀態。 在這種情況下為3(2013-10-04、05和06)。
像這樣的東西:
Status ID Total_consecutive
------- --- ------------------
A 1 2
I 1 3
提前致謝。
該解決方案還將為您提供開始日期和結束日期:
DECLARE @MyTable TABLE
(
ID INT,
[Status] CHAR(1),
[Date] DATE
);
INSERT @MyTable (ID, [Status], [Date])
SELECT 1, 'I', '2013-10-01' UNION ALL
SELECT 1, 'A', '2013-10-02' UNION ALL
SELECT 1, 'A', '2013-10-03' UNION ALL
SELECT 1, 'I', '2013-10-04' UNION ALL
SELECT 1, 'I', '2013-10-05' UNION ALL
SELECT 1, 'I', '2013-10-06' UNION ALL
SELECT 1, 'A', '2013-10-07' UNION ALL
SELECT 1, 'I', '2013-10-08';
SELECT y.ID,
y.[Status],
y.GroupID,
Start = MIN(y.[Date]),
[End] = MAX(y.[Date]),
[Days]= DATEDIFF(DAY, MIN(y.[Date]), MAX(y.[Date])) + 1
FROM
(
SELECT x.ID,
x.[Status],
x.[Date],
GroupID = DATEDIFF(DAY, 0, x.[Date]) - ROW_NUMBER() OVER(PARTITION BY x.[ID], x.[Status] ORDER BY x.[Date])
FROM @MyTable x
) y
GROUP BY y.ID, y.[Status], y.GroupID
HAVING MIN(y.[Date]) <> MAX(y.[Date]);
結果:
ID Status GroupID Start End Days
-- ------ ------- ---------- ---------- ----
1 A 41546 2013-10-02 2013-10-03 2
1 I 41547 2013-10-04 2013-10-06 3
我相信這會給您正確的結果:
declare @t table
(
ID INT,
[Status] CHAR(1),
[Date] DATE
);
insert @t (ID, [Status], [Date])
values (1, 'I', '2013-10-01'),
(1, 'A', '2013-10-02'),
(1, 'A', '2013-10-03'),
(1, 'I', '2013-10-04'),
(1, 'I', '2013-10-05'),
(1, 'I', '2013-10-05'),
(1, 'I', '2013-10-05'),
(1, 'I', '2013-10-06'),
(1, 'A', '2013-10-10')
;with a as
(
select ID, [Status], [Date],
row_number() over (partition by id order by [Status], [Date])-
row_number() over (partition by id order by [Date], [Status]) rn1
from @t
)
select ID, [Status], min([Date]) Start, max([Date]) [End],
count(*) [Total_consecutive]
from a
group by id, [Status], rn1
having count(*) > 1
結果:
ID Status Start End Total_consecutive
1 A 2013-10-02 2013-10-03 2
1 I 2013-10-04 2013-10-06 5
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