[英]Forcing button to cause postback
我有一個按鈕,它將導致創建一個彈出窗口:
<ItemTemplate>
<asp:Button ID="viewHoursButton" runat="server" Text="View Hours" OnClick="viewHoursButton_OnClick" />
<ajaxToolkit:ModalPopupExtender ID="viewHoursPopup" runat="server"
TargetControlID="viewHoursButton"
PopupControlID="viewHoursPanel"
CancelControlID="closeInfoPanelButton2"
DropShadow="true">
</ajaxToolkit:ModalPopupExtender>
<asp:Panel ID="viewHoursPanel" runat="server" CssClass="infoPanel">
//content of panel including gridview
</asp:Panel>
</ItemTemplate>
彈出的面板具有gridview,並且在按下按鈕時會傳遞一個SQL參數。 :
protected void viewHoursButton_OnClick(object sender, EventArgs e)
{
Button btn = sender as Button;
GridViewRow row = btn.NamingContainer as GridViewRow;
SqlDataSource6.SelectParameters["nonScrumStoryId"].DefaultValue = storyGridView.DataKeys[row.RowIndex].Values[0].ToString();
var viewHoursGridView = storyGridView.FindControl("viewHoursGridView") as GridView;
if (viewHoursGridView != null)
{
viewHoursGridView.DataBind();
}
}
問題是因為沒有回發到服務器,所以無法顯示gridview。 當向ajaxToolkit:ModalPopupExtender添加按鈕時,將發生回發。 我該如何找回?
嗨,我使用此代碼Javascript關閉彈出窗口並刷新父Web表單
Dim str_java As String = "<script language='javascript'>"
str_java += (" window.onunload = refreshParent; ")
str_java += (" function refreshParent() { ")
str_java += (" window.self.location.reload(true); } ")
str_java += (" window.close(); ")
str_java += ("</script>")
ScriptManager.RegisterStartupScript(Me, GetType(Page), "cerrarpagina", str_java, False)
這可以幫助你
您可以通過將__doPostBack
附加到事件來使用Javascript強制回發。
function doClick(sender, e) {
__doPostBack(sender,e);
}
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